The values of the letters in coordinates (a, b) and (c,d) are;
<u><em>a = -4</em></u>
<u><em>b = -6</em></u>
<u><em>c = 2</em></u>
<u><em>d = 6</em></u>
<u><em /></u>
We are given two equations;
-6x + 3y = 6 ---(eq 1)
x² + y = 10 ---(eq 2)
- We are told that they intersect at coordinates; (a, b) and (c, d).
Let us make y the subject in eq 2 to get;
y = 10 - x² --(eq 3)
- Let us put 10 - x² into eq 1 to get;
-6x + 3(10 - x²) = 6
expanding further gives;
-6x + 30 - 3x² = 6
rearranging gives;
3x² + 6x - 24 = 0
Using online quadratic equation <em>solver</em>, we have;
x = -4 and x = 2
Putting x = -4 into eq 3 gives;
y = 10 - (-4)²
y = 10 - 16
y = -6
Putting x = 2 into eq 3 gives;
y = 10 - (2)²
y = 10 - 4
y = 6
- Thus, the coordinates are; (-4, -6) and (2, 6)
Comparing with (a, b) and (c,d), we have;
a = -4
b = -6
c = 2
d = 6
Read more at; brainly.com/question/15165519
Answer:
Weight on 1 may = 104 lb
Step-by-step explanation:
Given:
Weight on last may = 110 lb
Weight gain for to week = 2 x 19 = 38 lb
Weight lose for to week = 2 x 22 = 44 lb
Find:
Weight on 1 may
Computation:
Weight on 1 may = Weight on last may - Weight gain for to week + Weight lose for to week
Weight on 1 may = 110 - 44 + 38
Weight on 1 may = 104 lb
Answer:
y(x) = -2x -8
Step-by-step explanation:
using the hint, insert the points (x,y) in the equation:
-2 = -3m + b eq1
2 = -5m + b eq2
eq2 - eq1 :
4 = -2m ==> m = -2
insert m in eq1:
-2 = -3*(-2) +b ==> b = -8
What do I solve? We need more info
the answer is x= 10.
the steps would go like this.
4 + 3/5 × (15 + 2x) = 25
4 + 9 + 6/5x = 25
13 + 6/5x = 25
65 + 6x = 125
6x = 125 -65
6x = 60
x = 10
hope this helps
