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3 years ago

What is the solution to the system of equations? y = 1/3x – 10 2x + y = 4

1 answer:

7 0

Y = 1/3 x - 10 . . . (1)
2x + y = 4 . . . . . (2)

Putting (1) into (2) gives
2x + 1/3 x - 10 = 4
7/3 x = 4 + 10 = 14
x = (3 x 14)/7 = 3 x 2 = 6
x = 6

From (1), y = 1/3 (6) - 10 = 2 - 10 = -8
y = -8

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Answer:

(4, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Coordinates (x, y)
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x - 7

y = -x + 5

Step 2: Solve for x

Substitution

Substitute in y: 2x - 7 = -x + 5
[Addition Property of Equality] Isolate x terms: 3x - 7 = 5
[Addition Property of Equality] Isolate x term: 3x = 12
[Division Property of Equality] Isolate x: x = 4

Step 3: Solve for y

Define original equation: y = -x + 5
Substitute in x: y = -4 + 5
Add: y = 1

7 0

3 years ago