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3 years ago

I ONLY HAVE A LITTLE TIME ANS NEED HELP!!!!! can someone explain this to me

Mathematics

2 answers:

denpristay [2]3 years ago

4 0

Answer:

x = 92

Step-by-step explanation:

$\frac{x}{46} =\frac{78}{39}$

I did big side over small side, proportions.

Cross Multiply.

39x = 3,588

divide by 39x

x = 92

Serhud [2]3 years ago

4 0

Answer:

Step-by-step explanation:

These triangles are similar because they share a common angle and two pairs of sides in the same ratio.

Sides of the bigger triangle are double of those of the smaller triangle

46+46 = 92

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Simplify this algebraic expression z-4/4+8

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Answer: (Z-4)/12

Step-by-step explanation:

(Z-4)/(4+8)

4+8 equals 12

(Z-4)/12

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3 years ago

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how many gallons of 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifr

ololo11 [35]

Let's say we'll mix "x" amount of the 80% solution, how much antifreeze is in it? well is just 80% of antifreeze, and the rest is something else.... what's 80% of "x"? so is (80/100)*x, or 0.8x.

likewise, the mixture will be a 70% solution, and let's say it adds up to "y" amount, so how much antifreeze is in it? well (70/100) * y or 0.7y.

$\bf \begin{array}{lccclll}
&\stackrel{gallons}{amount}&\stackrel{\%}{quantity}&\stackrel{antifreeze}{quantity}\\
&------&------&------\\
\textit{80\% sol'n}&x&0.80&0.8x\\
\textit{10\% sol'n}&100&0.10&10\\
------&------&------&------\\
mixture&y&0.70&0.7y
\end{array}$

so whatever "x" is, we know that x + 100 = y.

and we know that 0.8x + 10 = 0.7y.

$\bf \begin{cases}
x+100=\boxed{y}\\
0.8x+10=0.7y\\
----------\\
0.8x+10=0.7\left( \boxed{x+100} \right)
\end{cases}
\\\\\\
0.8x+10=0.7x+70\implies 0.8x-0.7x=70-10\implies 0.1x=60
\\\\\\
x=\cfrac{60}{0.1}\implies x=600$

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3 years ago

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yanalaym [24]

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Answer:

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Step-by-step explanation:

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4 years ago

Goes through every edge exactly one; starts and stops at different places. a Hamiltonian Path b Hamiltonian Circuit c Euler Path

Mariana [72]

Answer:

D. Euler Circuit.

Step-by-step explanation:

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