Vertex form is:
f(x) = -5(x+10)^2 + 508
Well, we know that the legs of this triangle are equal, and we know
that the area of any triangle is (1/2)(base)(height) .
Since this is a right triangle, we can set it down on one leg, and then
the other leg will be the height. Then ...
Area = (1/2) (base) (height)
= (1/2) (leg) (leg)
65 cm² = (1/2) (leg)²
Multiply each side by 2 : 130 cm² = (leg)²
Take the square root of each side: leg = √130 cm² = 11.402 cm
rounded to the nearest tenth: 11.4 cm
Answer:
q- p + 1
Step-by-step explanation:
Let p(x) = x³ + px² + qx + r
p(-1) = 0
(-1)³+p(-1)²+q(-1) + r = 0
-1+ p -q + r = 0
r = q- p + 1
The triangle is 4 times bigger so multiply 25 by 4 that will give you 100 =6x + 28
subtract 28 from both sides then divide 6 by the answer you get after subtracting.
x = 12
6 times 12 equals 72. 72 plus 28 equals 100.
One point on the line is (1,3) and another point is (9,11).
Find the slope of the two points on the line.

Now, let's make our equation in the form of y = mx + b, where m is the slope and b is the y-intercept.
We now have y = 1x + b
Plug in a point and solve for b.
y = 1x + b
3 = 1(1) + b
3 = 1 + b
b = 2
The equation is
y = x + 2.