Question

A toy manufacturer produces the same toy in 4 different colors: red, blue, green, and yellow. The toy manufacturer has 5 production lines dedicated to the red version, 5 production lines dedicated to the blue version, 4 production lines dedicated to the green version, and 2 production lines dedicated to the yellow version. A toy has an equal chance of traveling down any production line. What is the probability that the toy will not be green?

Answer 1

Answer:

The probability that the toy will not be green is 3/4 or 0.75

Step-by-step explanation:

Consider the provided information.

A toy manufacturer produces the same toy in 4 different colors: red, blue, green, and yellow.

Production lines dedicated to the red = 5

Production lines dedicated to the blue = 5

Production lines dedicated to the green = 4

Production lines dedicated to the red = 2

We need to calculate the probability that that the toy will not be green.

The total number of toys are: 5 + 5 + 4 + 2  = 16 toys.

Total toys that are not green = 5 + 5 + 2 = 12 toys.

$Probability=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}$

Substitute the respective values in the above formula.

$Probability=\frac{12}{16}$

$Probability=\frac{3}{4}=0.75$

Hence, the probability that the toy will not be green is 3/4 or 0.75

Answer 2

5 + 5 + 4 + 2 = 16

16 - 4 = 12

12/16 = 3/4

The probability that the toy will not be green is 3/4.