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Valentin [98]
3 years ago
15

A toy manufacturer produces the same toy in 4 different colors: red, blue, green, and yellow. The toy manufacturer has 5 product

ion lines dedicated to the red version, 5 production lines dedicated to the blue version, 4 production lines dedicated to the green version, and 2 production lines dedicated to the yellow version. A toy has an equal chance of traveling down any production line. What is the probability that the toy will not be green?
Mathematics
2 answers:
melamori03 [73]3 years ago
7 0

Answer:

The probability that the toy will not be green is 3/4 or 0.75

Step-by-step explanation:

Consider the provided information.

A toy manufacturer produces the same toy in 4 different colors: red, blue, green, and yellow.

Production lines dedicated to the red = 5

Production lines dedicated to the blue = 5

Production lines dedicated to the green = 4

Production lines dedicated to the red = 2

We need to calculate the probability that that the toy will not be green.

The total number of toys are: 5 + 5 + 4 + 2  = 16 toys.

Total toys that are not green = 5 + 5 + 2 = 12 toys.

Probability=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}

Substitute the respective values in the above formula.

Probability=\frac{12}{16}

Probability=\frac{3}{4}=0.75

Hence, the probability that the toy will not be green is 3/4 or 0.75

telo118 [61]3 years ago
4 0
5 + 5 + 4 + 2 = 16

16 - 4 = 12

12/16 = 3/4

The probability that the toy will not be green is 3/4. 
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Svet_ta [14]

Answer:

1.

x1=1

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2.

x1=2

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5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

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7.

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y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

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midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

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