The vertices of the quadrilateral JKLM are J(-2,0), K(-1,2), L(1,3), and M(0,1). Can you use the slopes
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Hello there,
Well we are going to start off with the equation to find the slope based on the given points:
Now using the two given points we are going to plug in and solve:
=
=
From this you know that is the slope of the equation. However, to find the y-intercept we are going to use y = mx+ b and plug in one of the points to solve:
(-14) = (-22) + b
(-14) = (-11) + b
-3 = b
That means that the y-intercept is at (0, -3). Lastly, we are just going to plug all this into the slope-intercept form:
y = - 3
Hope I helped,
Amna