Well, this is absolute value, so as a mixed fraction you would have to times the denominator to the whole number, and then add the answer of that to the numerator (2 x 2 x 1). After that, you should get a whole number as an answer, but make it as a fraction. (put the whole number you got on top of the denominator before (2) to make it a fraction). Then, again, since it's absolute value, then it into a negative. Hope this helps and hope it not confusing!!
Answer:
steps below
Step-by-step explanation:
√576 = √64*9 = √(2)⁶*(3)² = 2³*3 = 24
√15876 = √4*81*49 = √2²*3⁴*7² = 2*3²*7 = 126
Answer:
174 square centimetres
Step-by-step explanation:
The formula for finding the surface area of a rectangular prism is
SA = 2LW + 2LH + 2HW
Therefore surface area will be
= 2(11*5) + 2(11*2) +2(2*5)
= 2 * 55 + 2 * 22 + 2 * 10
= (110 + 44 + 20) square cm
Which gives you 174 square centimetres.
Answer:
t=+4.06
Step-by-step explanation:
when the baseball hits the ground, the height will be 0.
h=0we are given that h=−16t2+64t+4.
this means that the height is 0 when −16t2+64t+4=0.−16t2+64t+4=0divide both sides by 4:−4t2+16t+1=04=0−4t2+16t+1=0 can be solved using the quadratic formula:t=−b±√b2−4ac2a, where at2+bt+c=0.at2+bt+c=−4t2+16t+1a=−4,b=16,c=1t=−b+√b2−4ac2aor−b−√b2−4ac2a−b+√b2−4ac2a=−16+√272−8=−0.06..−b−√b2−4ac2a=−16−√272−8=4.06 (3s.f.)we have 2 values for t:−0.06 and 4.06.
since time cannot be negative, only the positive value can be taken.
this is 4.06, to 3 significant figures.the time taken is 4.06 seconds.
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.