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timurjin [86]
4 years ago
14

I already figured this out, answers are marked by Arrows. 

Chemistry
1 answer:
Mariulka [41]4 years ago
6 0

1) a)  

Fe2+ = ferrous and Fe3+ = ferric

Other cations:

Sn2+ = stannous ion and Sn3+ = stannic

Co2+ = cobaltous and Co3+ = cobaltic

Pb2+ = plumbous and Pb4+ = plumbic


2) b)

Sulfate is an anion represented as: SO₄²⁻

Other Cations:

Iron(III) ion = Fe3+

Ca2+= calcium divalent cation

Mercurous ion = Hg₂²⁺

3) a)

Ionic compounds are composed of both, an anion (negatively charged ion) and a cation (positively charged ion). The bond is formed by the transfer of electrons from cation to anion.

4) c)

Sulfur hexafluoride (SF6) is a neutral molecule composed of two elements: S and F. Hence, it is a binary compound.

5) c)

Molecular compounds tend to be inorganic compounds typically composed of two or more non-metals. For example: water H2O and carbon dioxide CO2.

6) d)

The compound MxTy is not and acid and M is a non-metal. Thus it could be a metalloid, a binary molecular compound.

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If cells did not work together what would happen to the organisms
arlik [135]

Surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

<h3>Living organisms </h3>

Living organisms; be it plants or animals are any organic or living system composed of cells and function as an individual entity.

  • All living organisms share a number of key characteristics or functions such as movement, respiration, homeostasis, reproduction, growth, evolution, competition and others.

  • Animals and plants also posess systems such as the digestive, skeletal, transport, nervous, excretory, respiratory and reproductive system.

  • Living organisms are also taxonomically classified as either unicellular microorganisms or multicellular plants and animals

So therefore, surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

Learn more about living organisms:

brainly.com/question/17259533

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5 0
1 year ago
When solutions of silver nitrate and sodium chloride are mixed, silver chloride precipitates out of the solution according to th
kipiarov [429]

The concentration of the sodium chloride would be 0.082 M

<h3>Stoichiometric calculations</h3>

From the equation of the reaction, the ratio of AgCl produced to NaCl required is 1:1.

Mole of 46.6 g AgCl produced = 46.6/143.32 = 0.325 moles

Equivalent mole of NaCl = 0.325 moles.

Molarity of 0.325 moles, 3.95 L NaCl = mole/volume = 0.325/3.95 = 0.082 M

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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3 0
2 years ago
Read 2 more answers
Balance the following: ___ AlBr3+ ___ K---&gt; ___KBr+ ___ Al
Nataliya [291]
___AlBr3 + ___K -> ___KBr + ___ Al

1 AlBr3 + 3K -> 3KBr + 1 Al

hope this helps............
6 0
4 years ago
grapevine trimming and other aromatics can be wrapped in aluminum foil with a few holes poked in it to?
Juli2301 [7.4K]
I need a little more context but I believe you are correct
7 0
3 years ago
A compound has a pka of 7.4. to 100 ml of a 1.0 m solution of this compound at ph 8.0 is added 30 ml of 1.0 m hydrochloric acid.
Monica [59]
 Using the Henderson-Hasselbalch equation on the solution before HCl addition: pH = pKa + log([A-]/[HA]) 8.0 = 7.4 + log([A-]/[HA]); [A-]/[HA] = 4.0. (equation 1) Also, 0.1 L * 1.0 mol/L = 0.1 moles total of the compound. Therefore, [A-] + [HA] = 0.1 (equation 2) Solving the simultaneous equations 1 and 2 gives: A- = 0.08 moles AH = 0.02 moles Adding strong acid reduces A- and increases AH by the same amount. 0.03 L * 1 mol/L = 0.03 moles HCl will be added, soA- = 0.08 - 0.03 = 0.05 moles AH = 0.02 + 0.03 = 0.05 moles Therefore, after HCl addition, [A-]/[HA] = 0.05 / 0.05 = 1.0 Resubstituting into the Henderson-Hasselbalch equation: pH = 7.4 + log(1.0) = 7.4, the final pH.
6 0
4 years ago
Read 2 more answers
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