Answer:

Explanation:
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In this case, since the precipitation of the lead iodide is related to the iodide ion in solution, if we make react lead (II) nitrate with an iodide-containing salt, a possible chemical reaction would be:

In such a way, since 15.71 mL of a 0.5770-M solution of lead (II) nitrate precipitates out lead (II) iodide, we can first compute the moles of lead (II) nitrate in the solution:

Next, since there is a 1:2 mole ratio between lead (II) nitrate and iodide ions, we compute the moles of those ions:

Finally, since the mixing of the two solutions produce a final volume of 40.71 mL (0.04071 L), the resulting concentration (molarity) of the iodide ions in the student's unknown turns out:

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Answer:
Carbon Dioxide is an Infrared Radiation Absorber. The (CO2) molecules also emits the absorbed infrared (IR) radiation energy. The photon energy from the infrared radiation causes the CO2 molecule to vibrate. Only some of its vibrational modes absorb infrared radiation
Explanation:
Its linear structure is considered when working with the formula to calculate the number of molecular vibrational modes. It has 3n - 4 vibrational modes, where n is the number of atoms in a compound of CO2
With 3 atoms, CO2 has
3n−5=4 types or patterns of vibration
1. The symmetric stretch
2. The asymmetric stretch
3. The bend
The symmetric stretch vibrational mode is ir-inactive.
The asymmetric stretch is ir-active as it results in changes in dipole moment
The bend is ir-active as well as it results in a change in dipole moment too.
the answer is becasue i just had this question and i got got it wrong so te answer is 0.43
Answer:
We need 7.94 grams of Ca3(PO4)2
Explanation:
Step 1: Data given
Volume of Ca3(PO4)2 = 200 mL = 0.2 L
Molarity = 0.128 M
Molar mass of Ca3(PO4)2 = 310.18 g/mol
Step 2: Calculate moles of Ca3(PO4)2
Moles = molarity * volume
Moles Ca3(PO4)2 = 0.128 M * 0.2 L
Moles Ca3(PO4)2 = 0.0256 moles
Step 3: Calculate mass of Ca3(PO4)2
Mass Ca3(PO4)2 = moles Ca3(PO4)2 * molar massCa3(PO4)2
Mass Ca3(PO4)2 = 0.0256 moles * 310.18 g/mol
Mass Ca3(PO4)2 = 7.94 grams
We need 7.94 grams of Ca3(PO4)2
C) 5 protons, 5 electrons, and 6 neutrons