Answer:
Part 1) The measure of arc EHL is 
Part 2) The measure of angle LVE is 
Step-by-step explanation:
step 1
Let
x-----> the measure of arc EHL
y----> the measure of arc EVL
we know that
The measurement of the outer angle is the semi-difference of the arcs it encompasses.
so
we have
substitute
------> equation A
Remember that
-----> equation B ( complete circle)
substitute equation A in equation B and solve for x
Find the value of y
therefore
The measure of arc EHL is
The measure of arc EVL is 
step 2
Find the measure of angle LVE
we know that
The inscribed angle measures half that of the arc comprising
Let
x-----> the measure of arc EHL
we have
substitute
Answer:
After 11 weeks, Darnell′s savings account will have a total of $8,360.
Step-by-step explanation:
The data provided is as follows:
n: 1 2 3 4
f (n): 260 360 460 560
Consider the data for f (n).
The series f (n) follows an arithmetic sequence with a common difference of 100 and first term as 260.
The nth term of an arithmetic sequence is:
![a_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=a_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Compute the value of f (11) as follows:
![f(11)=\frac{11}{2}[(2\times260)+(11-1)\times 100]](https://tex.z-dn.net/?f=f%2811%29%3D%5Cfrac%7B11%7D%7B2%7D%5B%282%5Ctimes260%29%2B%2811-1%29%5Ctimes%20100%5D)
![=5.5\times[520+1000]\\\\=5.5\times 1520\\\\=8360](https://tex.z-dn.net/?f=%3D5.5%5Ctimes%5B520%2B1000%5D%5C%5C%5C%5C%3D5.5%5Ctimes%201520%5C%5C%5C%5C%3D8360)
Thus, after 11 weeks, Darnell′s savings account will have a total of $8,360.
Sin³ x-sin x=cos ² x
we know that:
sin²x + cos²x=1 ⇒cos²x=1-sin²x
Therefore:
sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0
sin³x=z
z³+z²-z-1=0
we divide by Ruffini method:
1 1 -1 -1
1 1 2 1 z=1
-------------------------------------
1 2 1 0
-1 -1 -1 z=-1
--------------------------------------
1 1 0 z=-1
Therefore; the solutions are z=-1 and z=1
The solutions are:
if z=-1, then
sin x=-1 ⇒x= arcsin -1=π+2kπ (180º+360ºK) K∈Z
if z=1, then
sin x=1 ⇒ x=arcsin 1=π/2 + 2kπ (90º+360ºK) k∈Z
π/2 + 2kπ U π+2Kπ=π/2+kπ k∈Z ≈(90º+180ºK)
Answer: π/2 + Kπ or 90º+180ºK K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
Answer:
B
Step-by-step explanation:
x²+2x=19 add 1 to both sides which gives you x²+2x+1=20
x²+2x+1 is the same as (x+1)²
Therefore (x+1)²=20
Answer:
2(x-1)=2x-2
Step-by-step explanation:
distribute the 2 into (x-1) so you get 2x-2 which is equal to 2x-2
