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3 years ago

A.What is the area, in square meters, of 6 triangles?

Mathematics

1 answer:

Dima020 [189]3 years ago

3 0

it is b thats the it

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One jar of crushed ginger costs $2. How<br> many jars can you buy for $4?

Lina20 [59]

Answer:

2 jars

Step-by-step explanation:

If one jar costs $2 and you have $4 then $2+$2=$4

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2 years ago

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If a polynomial is divided by a binomial and the remainder is zero, what does that tell you about the relationship between the b

OleMash [197]

Answer:

Step-by-step explanation:

The binomial is a factor of the polynomial.

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3 years ago

A wire is bent to form a square of side 22 cm. If the wire is re bent to form a circle, its radius is with steps

ExtremeBDS [4]

Step-by-step explanation:

the circumference of a circle is

C = 2×pi×r

with r being the radius.

the square side length is 22 cm. so, the circumference or perimeter of the square (and therefore the length of the wire) is

4×22 = 88 cm.

now, it is the same wire of the same length that is now forming a circle.

so, the circumference of the square is also the circumference of the circle.

therefore,

88 = 2×pi×r

44 = pi×r

r = 44/pi = 14.00563499... cm

so, rounded, radius = 14 cm.

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3 years ago

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Anyone know how to do this

blsea [12.9K]

Answer:

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3 years ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

3 years ago