A box (cube) has all equal edges or sides (s), thus the volume (v) of the cube is:
So since each side or edge around is 3 in, then the length around the square bottom of the box = 4×3 = 12 in
Answer:
A = 1, B = 0, C = 7
Step-by-step explanation:
The egg follows the path x = 7, so the equation is ...
1x +0y = 7
A = 1, B = 0, C = 7
A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.
b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.
c. If there are 54 respondents.
51 = yes, the rest is no.
= 54 - 51 = 3
= 3 is now divided to 54 = 3/54
= giving an answer of 0.0555
= 0.0555 x 100
= 5.6%
= The percent of responses that says 'no' is 5.6%
Answer:
Distance between the points A and B is 15.52 units.
Step-by-step explanation:
It has been given in the question that an airplane flies along a straight line from City A to City B.
Map has been laid out in the (x, y) coordinate plane and the coordinates of these cities are A(20, 14) and B(5, 10).
Distance between two points A'(x, y) and B'(x', y') is represented by the formula,
d = 
So we plug in the values of (x, y) and (x', y') in the formula,
d = 
d = 
d = 
d = 15.52
Therefore, distance between the points A and B is 15.52 units.
Answer:
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
Step-by-step explanation:
Given that;
mean x" = 5.4
standard deviation σ = 0.7
n = 6
Null hypothesis H₀ : μ = 5.0
Alternative hypothesis H₁ : μ > 5.0
∝ = 0.025
now,
t = ( 5.4 - 5.0) / ( 0.7/√6) = 0.4 / 0.2857 = 1.4
degree of freedom df = n-1 = 6 - 1 = 5
T critical = 2.571
Therefore; t < T critical,
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
