Answer:
7.21 units
Step-by-step explanation:
GIven data
Point 1= (8,3)
x1= 8
y1= 3
Point 2= (2,7)
x2= 2
y2= 7
The expression for the distance between two points is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((2-8)²+(7-3)²)
d=√((-6)²+(4)²)
d=√36+16
d=√52
d= 7.21
Hence the distance between the points is 7.21 units
Answer:
The (x,y) point of the vertex is usually labelled as:
Vertex = (h, k)
h = -b / 2a
k = ah^2 + bh + c
f(x) = -3x^2 + 12x -5
a = -3 b=12 c=-5
h = -12 / -6 therefore h = 2
k = -3*2^2 + 12*2 -5
k = -12 + 24 -5 therefore k = 7
Vertex (2, 7)
Source: http://www.1728.org/quadr3.htm
Step-by-step explanation:
Answer:
look at the sbse below
Step-by-step explanation:
∠DEC ≅ ∠DCE, ∠ACB ≅ ∠GEF,
∠B ≅ ∠F, DF ≅ BD
∠ACB ≅ ∠GEF, ∠B ≅ ∠F, DF ≅ BD, ΔABC ≅ ΔGFE.
i hope this helps you :) it took me a long time
The answer to this question is 5.35
