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bagirrra123 [75]
3 years ago
6

The sequence an = one third (3)n - 1 is graphed below: coordinate plane showing the points 2, 1; 3, 3; and 4, 9 Find the average

rate of change between n = 3 and n = 4. (6 points) negative one sixth one sixth −6 6
Mathematics
2 answers:
charle [14.2K]3 years ago
7 0

9514 1404 393

Answer:

  6

Step-by-step explanation:

The slope of the line between (3, 3) and (4, 9) is given by the slope formula:

  m = <average rate of change> = (y2 -y1)/(x2 -x1)

  m = (9 -3)/(4 -3) = 6/1

  m = 6

The average rate of change on the interval [3, 4] is 6.

Alborosie3 years ago
4 0

Answer:

the answer is 6

Step-by-step explanation:

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A random sample of 15 employees was selected. The average age in the sample was 31 years with a variance of 49 years. Assuming a
vova2212 [387]

Answer:

Assuming ages are normally distributed, the 98% confidence interval for the population average age is [26.3, 35.7].

Step-by-step explanation:

We have to construct a 98% confidence interval for the mean.

The information we have is:

- Sample mean: 31

- Variance: 49

- Sample size: 15

- The age is normally distributed.

We know that the degrees of freedom are

k=n-1=15-1=14

Then, the t-value for a 98% CI is t=2.625 (according to the t-table).

The standard deviation can be estimated from the variance as:

s=\sqrt {s^2}=\sqrt{49}=7

The margin of error is:

E=t_{14}*s/\sqrt{n}\\\\E=2.625*7/\sqrt{15}=18.375/3.873=4.7

Then, the CI can be constructed as:

M-t*s/\sqrt{n}\leq\mu\leq M+t*s/\sqrt{n}\\\\31-4.7\leq \mu \leq 31+4.7\\\\26.3\leq \mu \leq 35.7

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I hope this helps you:)

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