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3 years ago

1.the science club went on a two day field trip the first day the members

1 answer:

8 0

1. y=60n+15n y=95n+12n
2. y=15x+2
3. Equations that require multiple steps solve real world problems. This involves translating words into algebraic equations and solving them.

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Danielle has her finals coming up and she's worried she'll fail her class. Her past 3 test grades were a 72. an 85, and a 68. Sh

natka813 [3]

Answer:

Step-by-step explanation:

7 0

3 years ago

Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result

Vaselesa [24]

Complete Question:

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

Correct Answer:

A) $(10-x)(12-x)=15$

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

Step-by-step explanation:

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

$length=10-x\\breadth=12-x$

According to question , Area of new image is :

⇒ $Area = \frac{1}{8}Length(breadth)$

⇒ $Area = \frac{1}{8}(10)(12)$

⇒ $Area = 15$

So the equation will be :

⇒ $(10-x)(12-x)=15$

b. Find the dimensions of the reduced image

Let's solve : $(10-x)(12-x)=15$

⇒ $120-10x-12x+x^2=15$

⇒ $120-22x+x^2=15$

⇒ $x^2-22x+105=0$

By Quadratic formula :

⇒ $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $x = \frac{22 \pm8 }{2}$

⇒ $x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}$

⇒ $x = 15 , x =7$

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ $x =7$

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

5 0

2 years ago

Assume that the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. If th

ioda

Answer:

The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 69.0 inches and a standard deviation of 2.8 inches.

This means that $\mu = 69, \sigma = 2.8$