1.the science club went on a two day field trip the first day the members
1 answer:
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Answer:
(i) 15 m, 6 m/s
(ii) 90 m
Step-by-step explanation:
(i) For some acceleration (a) from rest, the distance covered (d) in time t is ...
d = (1/2)at^2
The distance covered by Ben in the 5 seconds he is accelerating is ...
d = (1/2)(1.2 m/s²)(5 s)² = 15 m
Of course, Ben's speed at that point is ...
s = (1.2 m/s²)(5 s) = 6 m/s
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(ii) When Ben has been walking 5 s, Alan has been walking 10 s, so Alan has covered (10 s)(4 m/s) = 40 m. Their distance difference of 40 -15 = 25 m is being made up at the rate of their speed differences: (6 m/s) -(4 m/s) = 2 m/s.
It will take (25 m)/(2 m/s) = 12.5 s additional time for Ben to catch Alan. In the 22.5 s that Alan has been walking before they meet, he will have walked ...
(22.5 s)(4 m/s) = 90 m . . . the distance OP
Question:
Howard is designing a chair swing ride. The swing ropes are 4 meters long, and in full swing they tilt in an angle of 23°. Howard wants the chairs to be 3.5 meters above the ground in full swing. How tall should the pole of the swing ride be? Round your final answer to the nearest hundredth.
Answer:
7.18 meters
Step-by-step explanation:
Given:
Length of rope, L = 4 m
Angle = 23°
Height of chair, H= 3.5 m
In this question, we are to asked to find the height of the pole of the swing ride.
Let X represent the height of the pole of the swing ride.
Let's first find the length of pole from the top of the swing ride. Thus, we have:
Substituting figures, we have:
Let's make h subject of the formula.
The length of pole from the top of the swing ride is 3.68 meters
To find the height of the pole of the swing ride, we have:
X = h + H
X = 3.68 + 3.5
X = 7.18
Height of the pole of the swing ride is 7.18 meters