All categories

4 years ago

The sum of -3 1/3b + b

Mathematics

1 answer:

vampirchik [111]4 years ago

6 0

-3 1/3 is -10/3. B is the same as 1b so you can change it to 3/3b. -10/3+3/3b is -7/3b

You might be interested in

Simplify.<br> <img src="https://tex.z-dn.net/?f=%5Csqrt32%20%2B%20%5Csqrt16%2B%20%5Csqrt8" id="TexFormula1" title="\sqrt32 + \sq

svetoff [14.1K]

Answer:

$4 + 6 \sqrt{2}$

Step-by-step explanation:

$\sqrt{32} + \sqrt{16} + \sqrt{8}$

$\sqrt{32} = \sqrt{4 \times 4 \times 2} = 4\sqrt{2}$

$\sqrt{16} = \sqrt{4 \times 4} = 4$

$\sqrt{8} = \sqrt{2 \times 2 \times 2} = 2 \sqrt{2}$

$4 + 4\sqrt{2} + 2 \sqrt{2} = 4 + 6 \sqrt{2}$

5 0

3 years ago

Plz help me I really need help

swat32

Answer:

it 2 parts away

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

9) Which point is a solution to the equation 3x + 2y = 9?<br> A. (0,4) B. (4,0) C. (1,3) D. (3, 1)

7nadin3 [17]

Answer:

c. (1, 3)

Step-by-step explanation:

The coordinates that best suite the equation, given it the answer.

4 0

3 years ago

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago

What is the slope of the line that passes through the points (-8, -1)(−8,−1) and (-6, -2) ?(−6,−2)? Write your answer in simples

ziro4ka [17]

The slope of line passing through the given points is: -1/2

Step-by-step explanation:

Given points are:

(x1,y1) = (-8,-1)

(x2,y2) = (-6,-2)

Slope is defined as the steepness of a line.

It is denoted by m.

The formula for slope is:

$m = \frac{y_2-y_1}{x_2-x_1}$

Putting the values

$m = \frac{-2-(-1)}{-6-(-8)}\\= \frac{-2+1}{-6+8}\\=\frac{-1}{2}$

The slope of line passing through the given points is: -1/2

Keywords: Slope, steepness

Learn more about slope at:

#LearnwithBrainly

3 0

4 years ago