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IRINA_888 [86]
3 years ago
10

Flying against the wind, an airplane travels 4500km in 6 hours. Flying with the wind, the same plane travels 2910 kilometers in

3 hours. What is the rate of the plane in still air and what is the rate of the wind?
Mathematics
1 answer:
katen-ka-za [31]3 years ago
7 0

Let <em>a</em> denote the airplane's speed in still air, and <em>w</em> the windspeed.

When the plane flies against the wind, it can travel an average speed of

(4500 km) / (6 h) = 750 km/h

so that

<em>a</em> - <em>w</em> = 750 km/h

Flying with the wind, it moves at a speed of

(2910 km) / (3 h) = 970 km/h

so that

<em>a</em> + <em>w</em> = 970 km/h

Add the two equations to eliminate <em>w</em> and solve for <em>a</em> :

(<em>a</em> - <em>w</em>) + (<em>a</em> + <em>w</em>) = 750 km/h + 970 km/h

2<em>a</em> = 1720 km/h

<em>a</em> = 860 km/h

Subtract them to eliminate <em>a</em> and solve for <em>w</em> :

(<em>a</em> - <em>w</em>) - (<em>a</em> + <em>w</em>) = 750 km/h - 970 km/h

-2<em>w</em> = -220 km/h

<em>w</em> = 110 km/h

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