Square root of 6 times 16 will give us 39.19
The square root of 48 times 32 [which gives us 1536] is also equal to 39.19
The square root of 1536 is equal to 39.19
Hence, x is equal to 32
Hope this helped! :D
Answer:
3. 11 (B)
6. (-2, 18) (D)
8. I see the answer choices now, it would be A.
I don't see any answer options, but anything that goes along the lines of the points form a line, it has a direct relationship, it is linear, etc.
Step-by-step explanation:
3. You are given the expression 6x^2 - 13 and told to evaluate it at x = 2
this yields 6(2)^2 -13 which is 24-13 = 11.
6. You are given the equation y = -9x and 4 choices for ordered pairs. Best way to do this is to plug in the values and see which one works. (But if you want to do this quick you realize that the since you are multiplying one of the values by a -9 this means that the signs of the ordered pair has to be opposite and that only occurs in D (-2, 18) Plug it in and it works.
8. Each time you pay for the meter, it costs $1 or 4 quarters. And you pay per hour. Therefore if the x - axis is time (hours) and the y axis was the number of quarters, you can see that for 1 hour you pay 4 quarters, 2 hours you pay 8 quarters, 3 hours you pay 12 quarters, etc.
You can connect the dots on the graph and you can see that it is linear, you can also verify this by finding the slope between each point and find that the slope (change in y / change in x) is all the same.
Answer:
x = -2, y = 21
Step-by-step explanation:
Let 4x + y = 13 to be equation1 {eqn1}
and let 5x - y = 5 to be equation2 {eqn2}
Using elimination method, you would try to make sure a particular unknown has the same value in both equation 1 and 2. This would make it easy for you to subtract one equation from the other.
Notice how the value of y is the same in both equations. That's a good sign.
But the signs aren't the same. Meaning y in eqn1 has a value of +1, and y in eqn2 has a value of -1. We need to make them similar.
So, we multiply the value of y in eqn1 by all the terms in eqn2. And, do pretty much the same thing by multiplying the value of y in eqn2 by all the terms in eqn1.
You would have:
-1 * (4x + y = 13)
+1 * (5x - y = 5)
This would result in;
-4x - y = -13 (eqn3)
5x - y = 5 (eqn4)
So, just subtract eqn3 from 4
You would have;
(5x - -4x) + (-y -- y) = (-13 - 5)
9x + 0 = -18
x = -18/9 = -2
and to find y;
just substitute the value of x into any of the 4 equations. let's try equation 1
Therefore;
4(-2) + y = 13
-8 + y = 13
y = 13 + 8 = 21
Answer:
alternate exterior
Step-by-step explanation: