Hi there!
200(20)^x > 500x + 400
Let's find the critical points of the inequality
200(20^x) = 500x + 400
Now we can divide both sides by 200
(200(20^x))/200 = (500x + 400)/200
20x^x = 5/2 x + 2
There are no critical points.
Thus,
The answer is: No solution
As always, it is my pleasure to help students like you.
Answer:
d) More than 3.
Step-by-step explanation:
The polynomial (x - 5)(x + 2) ( = x^2 - 3x + 10) has zeros of -2 and 5 but so have the polynomials formed by multiplying this by any integer:
- for example 2(x - 5)(x + 2) , 4(x - 5)(x + 2) and so on.
Answer:
(0,4) (3,5) (6,6)
Step-by-step explanation:
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Answer:
please mark me as brainlist please
Step-by-step explanation:
Correct option is D)
By property of similar triangle, we have
DE
AB
=
DC
BC
=
CE
AC
3
4
=
4.8
BC
=
4.2
AC
⇒ BC=6.4 and AC=5.6
Hence CA=5.6cm,DA=6.4cm
yes u multiple and divided so ans caome 150
