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puteri [66]
3 years ago
11

A bag contains 48 balls

Mathematics
1 answer:
FrozenT [24]3 years ago
6 0

Answer:

25 Balls

Step-by-step explanation:

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a hot air balloon is at an altitude of 240 feet. the balloon descends at 30 feet per minute. what equation gives the altitude y,
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To solve this problem you must follow the steps below:

1. The problem says that:

 - The<span> hot air balloon is at an altitude of 240 feet.
 - It descends at 30 feet per minute.

 2. Therefore, you have:

 x: the time in minutes.
 y: the altitute in feet.

 3. Keeping all this information on mind, you can write the following equation:

 y=240-30x

 4. Therefore, as you can see, the answer is:
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 y=240-30x
6 0
3 years ago
there were 132 children at the museum on Saturday. on Sunday, there were 61 children. how many children were there on Saturday a
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8 0
3 years ago
Read 2 more answers
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
4 years ago
Read 2 more answers
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