I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,
So,
So,
Hope this helps you!
Answer:
the first one
Step-by-step explanation:
Answer:
(1): "*-5x2y" was replaced by "*(-5x2y)".
(2): "x2" was replaced by "x^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(3x • (y2)) • (0 - (5x2 • y))
STEP
2
:
Equation at the end of step
2
:
3xy2 • -5x2y
STEP
3
:
Multiplying exponential expressions :
3.1 x1 multiplied by x2 = x(1 + 2) = x3
Multiplying exponential expressions :
3.2 y2 multiplied by y1 = y(2 + 1) = y3
I believe the answer is ( -3•5x3y3)
