Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.


Answer:0.11111111111
Step-by-step explanation:0.1 with a repeating decimal over the 1 because when you multiply 1/3 by 1/3 thats what you get.
Answer: 530.66 units²
<u>Step-by-step explanation:</u>

First round
137,638=100,000
52,091=50,000
Then add to get the estamate
100,000
+
50,000
150,000
Then to get the real answer add
1
137,638
+
52091
189,729