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Hello!! Can someone help me solve the equation 5.15x + 6 = 72.94 (I’m solving for x)

n200080 [17]

Answer:

A x = 13.00

Step-by-step explanation:

5.15x + 6 = 72.94

5.15x = 66.94

x = 12.998

3 0

3 years ago

Read 2 more answers

Please help!!! I’m going to insert bs equation here *4 + 6 = 10 is an example of an equation.*

Cloud [144]

Answer:

heart exclamation mark

Step-by-step explanation:

you could also maybe make it into a really badly done pokeball

6 0

3 years ago

The second side of a triangular deck is 3 feet longer than the shortest side and a third side that is 3 feet shorter than twice

matrenka [14]

Answer:

Shortest Side = 20 feet

Second Side = 23 feets

Third Side = 37 feets

Step-by-step explanation:

Let the shortest side of the desk be x. Hence,

Second side = (x + 3) feets

Third side = (2x - 3) feets

Perimeter = 80ft

x + (x + 3) + (2x - 3) = 80

4x = 80

x = 20

Hence, Second side = (20 + 3) feets

= 23 feets

Third side = (40 - 3) feets

= 37 feets

Hence, shortest side is 20 feets, Second side is 23 feets, Third side is 37 feets.

7 0

3 years ago

Help guys make p da subject of the formula

Basile [38]

Answer:

$p=\dfrac{m}{k-s}$

Step-by-step explanation:

When they ask you to make a variable the "subject of the formula", they're basically asking you to build a "machine" for it. In the expression $y=mx+b$ , for instance, if we know what m, x, and b are, we can plug them all in and out comes a value for y! To build that machine, we need to get it by itself on one side of the equation.

So, we want to build this machine for p, and the equation we have to build it out of is

$1=\dfrac{pk}{m+sp}$

One think we can immediately say about this equation: for a fraction to be equal to one, its numerator and denominator have to be equal to each other. So we can say

$m+sp=pk$

Ok, what next? Well, if we want p by itself, we need to somehow peel it off of that sp and pk. Let's collect them on the right side by subtracting sp from both sides:

$m=pk-sp$

p is a common factor of both sp and pk, so we can peel it away using the distributive property:

$m=p(k-s)$

And from here, we can divide both sides by $k-s$ and we'll have p as our subject:

$\dfrac{m}{k-s}=p$ or $p=\dfrac{m}{k-s}$

So if we know m, k, and s, we can easily solve for p. If m = 4, k = 2, and s = 0:

$p=\frac{4}{2-0} =\frac{4}{2}=2$

3 0

3 years ago

4. Assume that the chances of a basketball player hitting a 3-pointer shot is 0.4 and the probability of hitting a free-throw is

vovikov84 [41]

Answer:

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

Step-by-step explanation:

For each 3-pointer shot, there are only two possible outcomes. Either the player makes it, or the player does not. The same is valid for free throws. This means that both the number of 3-pointers and free throws made are given by binomial distributions.

Since 3-pointers and free throws are independent, first we find the probability of making exactly 3 3-pointers out of 10, then the probability of making exactly 5 free throws out of 10, and then the probability that the player will make exactly 3 3-pointers and 5-free throws is the multiplication of these probabilities.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of making 3 3-pointers out of 10:

The chances of a basketball player hitting a 3-pointer shot is 0.4, which means that $p = 0.4$ . So this is $P(X = 3)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.21499$

Probability of making 5 free throws out of 10:

The probability of hitting a free-throw is 0.65, which means that $p = 0.65$ . The probability is $P(X = 5)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{10,5}.(0.65)^{5}.(0.35)^{5} = 0.15357$

Calculate the probability that the player will make exactly 3 3-pointers and 5-free throws.

0.21499*0.15537 = 0.0334

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

5 0

3 years ago