Question

Square root 3a-2 = square root a/b (make b the subject)

Answer 1

Answer:

b = $\frac{a}{3a-2}$

Step-by-step explanation:

Given

$\sqrt{3a-2}$ = $\sqrt{\frac{a}{b} }$

Clear the radicals by squaring both sides

($\sqrt{3a-2}$ )² = ( $\sqrt{\frac{a}{b} }$ )², that is

3a - 2 = $\frac{a}{b}$ ( multiply both sides by b )

b(3a - 2) = a ← divide both sides by (3a - 2)

b = $\frac{a}{3a-2}$

Answer 2

Answer:

b = a/(3a-2)

Step-by-step explanation:

(3a-2)^½ = (a/b)½

Square both sides

3a - 2 = a/b

Reciprocate both sides

1/(3a-2) = b/a

b = a/(3a-2)