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Pavel [41]
3 years ago
13

What is 6 minus 4 1/3? (Fraction way)

Mathematics
1 answer:
Contact [7]3 years ago
6 0
Convert 6 to a mixed number 5 3/3 the subtract.5 3/3 -4 1/3=Answer = 1 2/3Your welcome!!!
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!!!! will give brainliest:
Nataly [62]

Answer:

the domain will be all real #'s bc the arrows are continuous/never ending. The range would be y<u><</u>4 because the line starts at 4 and goes down.

Hope this helped you :)

4 0
3 years ago
PLEASE ANSWER + BRAINLIEST !!!
Alchen [17]

x = 100 cm^2

d = 1.4*(x^1/2)

d = 1.4*(100^1/2)

d = 1.4*10

d = 14 cm

Hope this helps!

5 0
3 years ago
Find the value of x using the diagram below. Round to the nearest whole number. Picture Attached.
VashaNatasha [74]
Both triangles are right triangles. x is the hypotenuse of the upper one. ThePythagorean formula  will give the value of x. One side is known, The other side we will find using the fact that the lower right triangle is isosceles. The hypotenuse of an isosceles right triangle has a length of \sqrt{2} times the length of one of the legs. In this case 14. So the hypotenuse of the lower triangle is also the short side of the upper triangle. Using Pythagoras

25^{2} +  (14 \sqrt{2}) ^{2} = x^{2}

625 + 392 =  x^{2}

 1017 =  x^{2}

32 = x

4 0
3 years ago
Read 2 more answers
A farmer has one square mile land . If he divides his land into square fields that are 1/4 mile long and 1/4 mile wide,how many
White raven [17]

A square field that is 1/4 mile long and 1/4 mile wide has area

\dfrac{1}{4} \cdot \dfrac{1}{4} = \dfrac{1}{16}

So, to know how many of these fields fit in the biggest field, you have to divide their areas:

\dfrac{1}{\frac{1}{16}} = 16

So, if the farmer divides his land into square fields that are 1/4 mile long and 1/4 mile wide, he will have 16 of these smaller fields.

8 0
3 years ago
Bertha buys electricity from a company that offers a choice of two tariffs. Both have a daily charge of $0.20 regardless of how
Alenkasestr [34]

Answer: D ( 17/20)

Step-by-step explanation:

The two choices are:

The ‘standard’ tariff charges = $0.10 per unit

The ‘day/night tariff’ = $0.12 per unit for each unit consumed between 06:00 and 22:00 but only $0.05 for each unit consumed between 22:00 and 06:00

The day time is between 22:00 and 06:00

Time = 22 - 6 = 16 hours

Let assume that the charges are unit per hour.

For standard tariff = (16 × 0.10) + 0.2

Standard tariff = 1.6 + 0.2 = 1.8

For day/night = (16 × 0.12) + 0.2

= 1.92 + 0.2

= 2.12

The proportion will be

1.8/2.12 = 17/20 ( approximately)

6 0
3 years ago
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