2 years ago

What is the general form of the equation for the given circle?

Mathematics

1 answer:

Tom [10]2 years ago

4 0

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3x^2-192=0<br><img src="https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20%20-%20192%20%3D%200" id="TexFormula1" title="3 {x}^{2}

Murljashka [212]

$3x^2-192=0$
$3x^2=192$
$x^2=\frac{192}{3}$
$x=\pm \sqrt{64}$
$x=\pm 8$

x=-8 and x=8 are the solutions

5 0

2 years ago

Read 2 more answers

The parabolic arch of a bridge over a one-way road can be described by the equation y = -x^2 + 6, where x and y ar emeasured in

Vladimir [108]

So check the picture below

if we check the solutions or zeros for the equation, we get $\bf y=-x^2+6\implies 0=-x^2+6\implies x=\pm \sqrt{6}$

and as you can see in the picture, the value of "x" when y = 3.5, or the height of the truck is $\bf y=-x^2+6\implies 3.5=-x^2+6\implies x=\pm \sqrt{2.5}$

the truck, ends up with a clearance of $\bf \sqrt{2.5}-1.5$ on either side, so, the maximum clearance, the truck can have, those two clearances added together, $\bf 2(\sqrt{2.5}-1.5)$