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Rashid [163]
4 years ago
6

Write one digit on each side of 92 to make a four digit multiple of 45. How many different solutions does this problem have?

Mathematics
1 answer:
vitfil [10]4 years ago
8 0

Answer:

7920, 2925

Step-by-step explanation:

The four-digit number has to be a multiple of 5 and also a multiple of 9. So, the last number is either a 0 or a 5, and the addition of the 4 digits must be equal to 9, 18, 27, et cetera, like every multiple of 9.

For the case: _920, the addition of digits gives 11, then the only possible first digit is 18-11 = 7

For the case: _925, the addition of digits gives 16, then the only possible first digit is 18-16 = 2

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Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
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Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
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Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
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