Write one digit on each side of 92 to make a four digit multiple of 45. How many different solutions does this problem have?

Mathematics

1 answer:

vitfil [10]4 years ago

8 0

Answer:

7920, 2925

Step-by-step explanation:

The four-digit number has to be a multiple of 5 and also a multiple of 9. So, the last number is either a 0 or a 5, and the addition of the 4 digits must be equal to 9, 18, 27, et cetera, like every multiple of 9.

For the case: _920, the addition of digits gives 11, then the only possible first digit is 18-11 = 7

For the case: _925, the addition of digits gives 16, then the only possible first digit is 18-16 = 2

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natka813 [3]

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If s is true and j is false, is the following true or false (~s v j) ^ (s v~ j)

nexus9112 [7]

S = true
~s = false
-------------
j = false
~j = true
-------------
~s = false and j = false, so,
~s v j = (false) v (false)
~s v j = false
-------------
Similarly,
s v ~j = (true) v (true)
s v ~j = true
-------------
We have
~s v j = false
and
s v ~j = true
which lead to this when we conjunct the two logical expressions
(~s v j) ^ (s v ~j) = (false) ^ (true)
(~s v j) ^ (s v ~j) = false
-------------
-------------
The final answer is false

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Answer:

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Step-by-step explanation:

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Hope this helps! If it does please rate it the brainliest answer!