Help which one is right?

Mathematics

2 answers:

ladessa [460]1 year ago

7 0

Hope this helps! If it does please rate it the brainliest answer!

kap26 [50]1 year ago

4 0

Answer:

I think it is c

Step-by-step explanation:

I graphed it

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Consider the ex

natka813 [3]

An expression is defined as a set of numbers, variables, and mathematical operations. The value of x for which the expression (x-1)(x-7)=0 is 1 and 7.

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

For the given expression, (x-1)(x-7), the value of x for which the expression will be equal to 0 can be found by equation the factors of the expression to 0. Therefore,

x-1 = 0

x = 1

and

x-7=0

x = 7

Hence, the value of x for which the expression (x-1)(x-7)=0 is 1 and 7.

Learn more about Expression:

brainly.com/question/13947055

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8 0

2 years ago

What is the probability that a red marble will be pulled from a bucket of 250 red marbles and 300 blue marbles? Express the answ

PolarNik [594]

Answer:

5/11

Step-by-step explanation:

There are 250 red out of 550 total

250 / 550 = 5/11

5 0

3 years ago

Find the limit if it exists lim x→0 sqrtx+7-sqrt7 over x

Triss [41]

Answer:

$\frac{1}{ 2\sqrt{7} }$

Step-by-step explanation:

$\lim_{x\to 0} \frac{ \sqrt{x + 7} - \sqrt{7} }{x} \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} - \sqrt{7}) }{x} \times \frac{( \sqrt{x + 7} + \sqrt{7}) }{( \sqrt{x + 7} + \sqrt{7}) } \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} )^{2} - (\sqrt{7})^{2} }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{( {x + 7} - {7}) }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {\cancel x}}{\cancel x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {1}}{\sqrt{x + 7} + \sqrt{7}} \\ \\ = \frac{1}{ \sqrt{0 + 7} + \sqrt{7} } \\ \\ = \frac{1}{ \sqrt{7} + \sqrt{7} } \\ \\ = \frac{1}{ 2\sqrt{7} }$