given that a test statistic in a left tailed test is z equals -1.25, use a 0.05 significance level to find the p-value and state
the conclusion about the null hypothesis
1 answer:
Answer:
The <em>p-</em>value of the test is 0.106.
The null hypothesis will be accepted at 5% level of significance.
Step-by-step explanation:
The hypothesis test is left-tailed.
The test statistic value is: <em>z</em> = -1.25.
The significance level of the test is: <em>α</em> = 0.05.
The <em>p</em>-value of a left-tailed hypothesis test is:
The <em>p-</em>value of the test is 0.106.
**Use the <em>z-</em>table for the probability.
<u>Decision rule:</u>
If the <em>p</em>-value is less than the significance level the null hypothesis will be rejected and if it is more than the significance level the null hypothesis will be accepted.
The <em>p</em>-value = 0.106 > <em>α</em> = 0.05.
The null hypothesis will be accepted at 5% level of significance.
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Not sure if this is correct but I hope this helps :)
Not sure if this is correct but I hope this helps :)