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bonufazy [111]
3 years ago
13

given that a test statistic in a left tailed test is z equals -1.25, use a 0.05 significance level to find the p-value and state

the conclusion about the null hypothesis

Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0

Answer:

The <em>p-</em>value of the test is 0.106.

The null hypothesis will be accepted at 5% level of significance.

Step-by-step explanation:

The hypothesis test is left-tailed.

The test statistic value is: <em>z</em> = -1.25.

The significance level of the test is: <em>α</em> = 0.05.

The <em>p</em>-value of a left-tailed hypothesis test is:

p-value=P(Z

The <em>p-</em>value of the test is 0.106.

**Use the <em>z-</em>table for the probability.

<u>Decision rule:</u>

If the <em>p</em>-value is less than the significance level the null hypothesis will be rejected and if it is more than the significance level the null hypothesis will be accepted.

The <em>p</em>-value = 0.106 > <em>α</em> = 0.05.

The null hypothesis will be accepted at 5% level of significance.

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4.42×10^34 molecules/min

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