What's the correlation coefficient of this date . 10,11,16,9,7,15,16,10,96,51,62,58,89,81,46,51
dem82 [27]
Assuming the question is in the wrong format and"date" is data.
I chose X= 10,11,16,9,7,15,16,10 and Y= <span>96,51,62,58,89,81,46,51
the correlation cooefficent is
-0.3351
</span>
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
AC = 18, EB = 5 Step-by-step explanation:In a rhombus, AE = CE, and DE = BE. However, AE or AC ≠ DE or BE.
CE = AE
= 9
AC = CE + AE
= 9 + 9
= 18
DE = BE
= 5
Call Dawn's wage x, we will have Vesna's wage = x + 17 and Chris' wage = 4x(x + 17). So we have the equation:
Therefore, Chris's wage:
