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kotykmax [81]
3 years ago
11

Generalize the pattern by finding the nth term 2, 6, 12, 20...

Mathematics
1 answer:
Nastasia [14]3 years ago
8 0
32, 38, so on. So its +4 then +8 then +12 +16 +20....
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Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

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3 years ago
How do u write 5,823 in scientific notation
Alex73 [517]
<span>5.823 x 103 i hope it right ???</span>
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Complete the puzzle by clicking on the puzzle piece that contains equivalent expression.
Liono4ka [1.6K]

Answer:

 -5 when ...

Step-by-step explanation:

The rules of exponents can help you simplify the given product.

<h3>Rules</h3>

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  (ab)^c = (a^c)(b^c)

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

<h3>Application</h3>

  \left(\dfrac{x}{y}\right)^2(-x^2y)^3=\\\\\dfrac{x^2(-1)^3(x^2)^3y^3}{y^2}=-x^{2+2\cdot3}y^{3-2}=-x^8y

This expression does not match any of those offered.

When x=-1 and y=5, this becomes ...

  -(-1)^8(5)=\boxed{-5}

8 0
1 year ago
Solve for the questions (both of them) and label you answers for which question
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Jjbbh I don’t under stand
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A company rents riding equipment for a fixed amount plus a fee based on the number of days for which the equipment is rented. Th
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The answer is 6. I know that because I solved the question and I got 6 I'm positive its 6. Hope this helps.
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