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STALIN [3.7K]
3 years ago
14

n noisy factory environments, it's possible to use a loudspeaker to cancel persistent low-frequency machine noise at the positio

n of one worker. The details of practical systems are complex, but we can present a simple example that gives you the idea. Suppose a machine 6.0 m away from a worker emits a persistent 90 Hz hum. Part A To cancel the sound at the worker's location with a speaker that exactly duplicates the machine's hum, how far from the worker should the speaker be placed
Physics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

7.888m

Explanation:

Given:

frequency 'f'= 90Hz

velocity of the sound 'v' = 340 m /sec

The wavelength of the wave is given by,

λ= v/f => 340/90

λ= 3.777m

The destructive interference condition is givn by

Δd= (m+\frac{1}{2}  ) λ

where, m=0,1,2,3,..

m=0, for minimum destructive interference

Δd= (0+\frac{1}{2}  ) x 3.777

Δd=1.888

Therefore, the required distance is

d_f=d_i + Δd => 6 + 1.888

d_f= 7.888m

Thus, So the speaker should be placed at  7.888 m

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In a hydroelectric dam, water falls 35.0 m and then spins a turbine to generate electricity. Suppose the dam is 80% efficient at
anyanavicka [17]

Answer:

Height through the water falls h = 33 m

Efficiency of the of the unit

η

=

80

%

Power of the production unit

P

=

45

×

10

6

W

Acceleration due to gravity

g

=

9.8

m

/

s

Potential energy of one kg of water

Δ

U

=

m

∗

g

∗

h

=

1

∗

9.8

∗

33

=

323.4

J

Eighty percentage of the above energy is converted into electrical energy.

So eighty percentage of the potential energy of one kg of water

Δ

U

1

=

258.72

J

So mass of water required to flow per second to produce 45 MW of electricity in kilograms

M

=

P

Δ

U

1

=

45

∗

10

6

258.72

=

173933.2096

k

g

/

s

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Learn more about this topic:

Hydroelectric Energy: Definition, Uses, Advantages & Disadvantages

from Earth Science 101: Earth Science

Chapter 23 / Lesson 9

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Answer:

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