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STatiana [176]
3 years ago
13

The gravitational attraction between two objects will what is the object move further apart

Physics
1 answer:
finlep [7]3 years ago
3 0
The farther apart the two objects, the weaker the gravitational attraction between them.
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Velocity of an object of mass 5 kg increases from 3 m/s to 7 m/s on applying a force continuously for 2 s. Find out the force ap
Alenkasestr [34]

Answer:

Force=10N

Velocity=13m/s

Explanation:

Given,

Mass = 5kg

initial velocity=3m/s

Final velocity=7m/s

Time=2s

Now acceleration= v-u/t

=7-3/2

=4/2

=2m/s²

So, acceleration=2m/s²

Now,

F=ma

=5*2

=10N

7 0
2 years ago
A 615 N student standing on a scale in an elevator notices that the scale reads 645 N. From this information, the student knows
BARSIC [14]

Answer:

The elevator must be moving upward.

Explanation:

During the motion of an elevator, the weight of the person deviates from his or her actual weight. This temporary weight during the motion is referred to as "Apparent Weight". So, when the elevator is moving downward, the apparent weight of the person becomes less than his or her actual weight.

On the other hand, for the upward motion of the elevator, the apparent weight of the person becomes more than the actual weight of that person.

Since the apparent weight (645 N) of the student, in this case, is greater than the actual weight (615 N) of the student.

<u>Therefore, the elevator must be moving upward.</u>

8 0
3 years ago
A ticker tape of the motion of a trolley.Time taken for one tick is 0.02 seconds
Harrizon [31]

Answer:Hshshshshja

Explanation:

6 0
3 years ago
Ferns spread spores instead of seeds, and some ferns eject the spores at surprisingly high speeds. One species accelerates 1.4 μ
marta [7]

Answer:

Impulse is 6.3*10^{-9}\:N \cdot s

The average force is 6.3*10^{-6} N

Explanation:

When a mass m undergoes a change in velocity \Delta v, its impulse I is

I =m\Delta v

and if a force F is acting for time t, then the impulse I is given by

I=F*t

Now the mass of the spores in kg is

m=1.4*10^{-6}g*\frac{10^{-3}kg}{g}=1.4*10^{-9}kg

we calculate the impulse from the first formula:

I =m\Delta v =(1.4*10^{-9}kg)(4.5\frac{m}{s} )=6.3*10^{-9}N\cdot s

\boxed{I=6.3*10^{-9}\:N \cdot s}

Now that we have impulse, we calculate the average force on the spore from the second formula:

F=\frac{I}{t} =\frac{6.3*10^{-9}}{1*10^{-3}s}=6.3*10^{-6} N

\boxed{F=6.3*10^{-6} N}

5 0
4 years ago
Two long cylinders of radii 5 cm and 10 cm form a coaxial cylindrical capacitor, the space between them being filled with a diel
V125BC [204]

Answer:

21

Explanation:

8 0
3 years ago
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