The gravitational attraction between two objects will what is the object move further apart

What process is represented by this redox equation ? 6H 2 O+6CO 2 C 6 H 12 O 6 +6O 2

IgorC [24]

<h2>Question:-</h2>

What process is represented by this redox equation ?

6H 2 O+6CO 2 C 6 H 12 O 6 +6O 2

<h2>Answer:-</h2>

This equation is of the process of photosynthesis. The proper equation is :-

6CO2+6H2O→C6H12O6+6O2.

8 0

4 years ago

What measures wind speed?

zhannawk [14.2K]

The speed of that wind can be measured using a tool called an anemometer. An anemometer looks like a weather vane, but instead of measuring which direction the wind is blowing with pointers, it has four cups so that it can more accurately measure wind speed.i hope that this helps you out, have an amazing day!!

6 0

3 years ago

Read 2 more answers

A 250 kg crate is placed on an adjustable inclined plane. If the crate slides down the incline with an acceleration of 0.7 m/s2

stepladder [879]

Answer:

21.2 degrees

Explanation:

Let gravitational acceleration constant g = 9.81 m/s2 directed downward. We can calculate the g component that is parallel to the 25 degree incline:

$gsin25^0 = 9.81sin25^0 = 4.15 m/s^2$

This parallel component would produce an acceleration of the block. But since the net acceleration is only 0.7 m/s2, there's a friction acceleration that hinders g parallel. This acceleration can be calculated by

$4.15 - a_f = a = 0.7$

$a_f = 4.15 - 0.7 = 3.45 m/s^2$

The force of friction would be

$F_f = a_fm = 250 * 3.45 = 816.5 N$

Friction is a product of normal force and its coefficient

$F_f = \mu N = \mu mgcos25^0 = \mu 250*9.81*cos25^0 = 2222.72 \mu$

$\mu = F / 2222.72 = 816.5 / 2222.72 = 0.388$

For the crate to slide down at constant speed, the net acceleration must be 0. In other words, the parallel g must be the same as acceleration caused by friction. Let this incline angle be α

$g sin\alpha = a_f = F_f/m = \frac{\mu N}{m} = \frac{\mu mgcos\alpha}{m} = \mu g cos\alpha$

$sin\alpha = \mu cos\alpha$

$\frac{sin \alpha}{cos \alpha} = \mu$

$tan\alpha = \mu = 0.388$

$\alpha = tan^{-1} 0.388 = 0.37 rad = 0.37*180/\pi \approx 21.2^0$

6 0

4 years ago

The x and y components of a force are 2 N and - 3 N. The force is

jarptica [38.1K]

Answer:

Your answer is in the pic

3 0

3 years ago

A positive charge is placed at rest at the center of a region of space in which there is a uniform electric field. (A uniform fi

Harlamova29_29 [7]

Answer:

.D.It will decrease because the charge will move in the direction of the electric field

Explanation:

which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.

solution

The potential energy decreases, converted to kinetic energy

The charge will feel a force in the direction of the electric field (F=Eq) and thus it will accelerate with

a constant acceleration. (Just like releasing an object above the earth's surface - constant acceleration,

at least until it hits something.)

tus te answer will be

.D.It will decrease because the charge will move in the direction of the electric field

7 0

3 years ago