K=1/2(mass)(velocity)^2
Mass=1.0
Velocity=5.0
K=1/2(1)(5)^2
K=12.5 J
The first and third choices could both do it, but the first choice makes a much better, clear demonstration.
Input energy is: 200 joule
Output energy is: 100 joule
100/200*100=%50 efficiency
Explanation:
According to the law of conservation of energy
,
Potential energy = kinetic energy
I =
mgh =
v = 7.4 m/s
thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.