3 years ago

If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does it have?

Physics

1 answer:

aksik [14]3 years ago

8 0

Answer: 2200J

Explanation:

M = 44kg

V = 10m/s

K.E =?

K.E = 1/2MV2 = 1/2 x 44 x (10)^2

K.E = 22 x 100

K.E = 2200J

You might be interested in

What is the kinetic energy of a 1.0-kg billiard ball that moves at 5.0 m/s?

romanna [79]

K=1/2(mass)(velocity)^2
Mass=1.0
Velocity=5.0
K=1/2(1)(5)^2
K=12.5 J

3 0

2 years ago

Please need help with this

lutik1710 [3]

The first and third choices could both do it, but the first choice makes a much better, clear demonstration.

8 0

3 years ago

Read 2 more answers

Write and solve a MA or efficiency problem

GuDViN [60]

Input energy is: 200 joule
Output energy is: 100 joule

100/200*100=%50 efficiency

8 0

2 years ago

A solid cylinder with a mass of 2.72 kg and a radius of 0.083 m starts from rest at a height of 4.20 m and rolls down a 88.7 ◦ s

Bingel [31]

Explanation:

According to the law of conservation of energy ,

Potential energy = kinetic energy

$mgh = \frac{1}{2} \times mv^{2} + \frac{1}{2} \times I \times \omega^{2}$

I = $\frac{mr^{2}}{2}$

$\omega = \frac{v}{r}$

$mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]$

mgh = $[\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]$

$g \times h = \frac{3}{4} \times v^{2}$

$9.8 \times 4.2 = \frac{3}{4} \times v^{2}$

v = 7.4 m/s

thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.

5 0

2 years ago

If a positively charged particle moves into a magnetic field traveling in a straight line, how would you expect it's motion to c

MrMuchimi

It would begin to curve toward the magnetic pull

6 0

2 years ago

Read 2 more answers