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brilliants [131]
3 years ago
6

Two​ researchers, Jaime and​ Mariya, are each constructing confidence intervals for the proportion of a population who is​ left-

handed. They find the point estimate is 0.27. Each independently constructed a confidence interval based on the point​ estimate, but​ Jaime's interval has a lower bound of 0.242 and an upper bound of 0.298​, while​ Mariya's interval has a lower bound of 0.188 and an upper bound of 0.286. Which interval is​ wrong? Why?
Mathematics
1 answer:
alekssr [168]3 years ago
8 0

Answer:

Mariya​'s interval is wrong because it is not centered on the point estimate

Step-by-step explanation:

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Answer: 0.03

Step-by-step explanation:

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Simplify !!<br> answer choices:<br> 4^5/6<br> 4^3/2<br> 4^1/6<br> 4^1/3
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C

Step-by-step explanation:

In the attached file

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Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
Justin did push-ups for the past 5 days. The following data points are the number of push-ups he did each day.
irga5000 [103]

Answer:

2.67

Step-by-step explanation:

6 0
3 years ago
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A construction worker needs to put a rectangular window in the side of a building. He knows from measuring that the top and bott
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Answer: 5 feet

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One length of the window is 5 feet. Since the last side is opposite to the length of the window, it has the same length, i.e., its value is 5 feet.

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