Year Sam Sally1: X (3/2)X-10002: (5/2)X-2000 2X-15003: X/5+1000 X/4+1400Total 37X/10-1000 15X/4-1100
Since their investments are known to be equal, we equate the two totals and solve for X.37X/10-1000=15X/4-1100(150-148)X/40 = 1100-1000X/20=100X=2000
So Sam invested $2000 the first year.Sally invested X/4+1400=1900 in the last year.

6 0

3 years ago

Helllllppp!!!!!!!!!!!!11 marking brainliest!

aalyn [17]

Hello!

Let the unknown number be x.

Subtract 5:

x-5

Double the result: (multiply the result times 2):

2(x-5)

Hope everything is clear.

Let me know if you have any questions!

#KeepLearning

:-)

4 0

2 years ago

suppose that r(x) is a polynomial of degree 9 whose coefficients are real numbers. also, suppose that R(x) has the following zer

liberstina [14]

The polynomial R(x) has degree 9. Two of the roots are 2i and -4-i.

(a) As the non-real roots lies along with its conjugates, the other roots of R(x) will be,

-2i and -4+i.

(b) The maximum number of real zeroes R(x) can have is 5, as there are 4 non-real roots that already exists.

(c).The maximum number of non real zeroes R(x) can have is 4.

7 0

1 year ago