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Mathematics

1 answer:

harina [27]2 years ago

8 0

$\dfrac{f(2+h)-f(2)}{h}=\dfrac{(2+h)^2+2(2+h)-1-(2^2+2\cdot2-1)}{h}=\\\\=\dfrac{4+4h+h^2+4+2h-1-(4+4-1)}{h}=\dfrac{h^2+6h+7-7}{h}=\dfrac{h^2+6h}{h}=h+6$

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Yuki888 [10]

Answer:

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Step-by-step explanation:

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As we know

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replacing y by x in the above expression

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