The given expression is:
![\sqrt[5]{64 x^{7} w^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20)
The expression can be simplified as follows:
![\sqrt[5]{64 x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{6} x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{5}*2* x^{5}* x^{2} * w^{5} } \\ \\ = \sqrt[5]{ (2^{5} x^{5} w^{5} )*2 x^{2} } \\ \\ = \sqrt[5]{(2xw)^{5}*2 x^{2} } \\ \\ =2xw* \sqrt[5]{2x^{2} } ](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B6%7D%20%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B5%7D%2A2%2A%20x%5E%7B5%7D%2A%20x%5E%7B2%7D%20%2A%20w%5E%7B5%7D%20%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%20%282%5E%7B5%7D%20%20x%5E%7B5%7D%20%20w%5E%7B5%7D%20%29%2A2%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282xw%29%5E%7B5%7D%2A2%20x%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D2xw%2A%20%5Csqrt%5B5%5D%7B2x%5E%7B2%7D%20%7D%20%0A%20)
Answer:
x = -2, x = 2
Step-by-step explanation:
The denominator factors as ...
x^2 -4 = (x -2)(x +2)
The numerator has no factors that cancel either of these, so the function will have vertical asymptotes where the denominator is zero: at x = -2 and x = 2.
Answer:
BZ = 64/23 = 2 18/23
Step-by-step explanation:
The angle bisectors divide the triangle into proportional parts, so we have ...
CB/CY = AB/AY
CB = CY(AB/AY) = 4(8/6) = 16/3 . . . . multiply by CY and evaluate
and ...
BZ/CB = AZ/AC
BZ = AZ(CB/AC) . . . . multiply by CB
But we have ...
AZ = 8 -BZ, so this becomes ...
BZ = (8 -BZ)(16/3)/(10)
BZ(1 +8/15) = 64/15 . . . . add the BZ term on the right to both sides
BZ = (64/15)(15/23) = 64/23 . . . . divide by the coefficient of BZ
BZ = 64/23 = 2 18/23
Answer:
<h2>(-2, 5)</h2>
Step-by-step explanation:
