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yarga [219]
3 years ago
14

Please help me with my homework!!!!

Mathematics
1 answer:
Zina [86]3 years ago
8 0

Answer:

∠ACB= 57°

AB= 8.80 units (3 s.f.)

AC= 10.1 units (3 s.f.)

Step-by-step explanation:

Please see attached picture for full solution.

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A coin was flipped 10 times and 4 of the 10 flips resulted in heads. Compare the experimental probability of flipping heads to t
AVprozaik [17]

Answer:

the experimental probability is Less than the theoretical probability

7 0
2 years ago
Write a fraction that is less than 5/6 and has a denominator of 8
KatRina [158]
You'll want to make a common denominator with 6 and 8.
That denominator would be 24.
24/6=4 so you would have to multiply 5/6 by 4/4 to get 20/24.
Next, 24/8=3 so 1/8 could be multiplied by 3/3 to get 3/24.
Since 3 is less than 20, 1/8 is smaller than 5/6.

If you want the same numerator, 5/8 = 15/24. This would make 5/8 smaller than 5/6 as well.
The highest eighth you can go is 6/8 which is 18/24.
So you can use any numerator between 1 and 6 with a denominator of 8 to get a fraction smaller than 5/6.
3 0
3 years ago
A. (1.34)(5.46) = (1.76)(x)
Alja [10]
We are given an equation with an unknown variable x. We can find the value of x by dividing both sides by 1.76, as this will leave only x on the right hand side of the equation and its value on the left hand side, as shown below:

(1.34)(5.46)=1.76(x) \\  \\ 
 \frac{(1.34)(5.46)}{1.76} = \frac{1.76(x)}{1.76}  \\  \\ 
 \frac{(1.34)(5.46)}{1.76} =x \\  \\ 
4.16=x

Thus solving the given equation, we get x =4.16, rounded of to nearest hundredth. 
6 0
3 years ago
I got a 12 discount on a pair of jeans and a 25% discount on a t-shirt the original price of the jeans was $100 and thatof the T
Tcecarenko [31]

Answer:

$125.50

but I'm not sure

Step-by-step explanation:

100÷100=1

1×12=12

100-12=88

jeans with discount = $88

50÷100=0.5

0.5×25=12.50

5000-1250=3750

t-shirt with discount = $37.50

3750+8800=12550

6 0
2 years ago
Read 2 more answers
What is greater than 40 but less than 20
Paladinen [302]
I've already been complemented twice on my previous answer, but then I discovered that I mis-read the question.  My entire original answer was wrong, and I have to delete it.

I don't believe that any number can satisfy both of those conditions.
I'll say the question has no answer.
3 0
3 years ago
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