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Alex Ar [27]
3 years ago
11

Please I need help how do you solve 5 + x to the 2nd power = 2x2 + 13

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

it has no real solutions

Step-by-step explanation:

5 + x² = 2x² + 13

first simplify by moving the 2x² to the left and the 5 to the right:

x² - 2x²=  13 - 5

- x²=  8

x = +/- √-8 has no (real) solutions

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Factor the following trinomial expression by a method of your choice: 3x2 + 7x-10.
polet [3.4K]
3x² + 7x - 10
3x² - 3x + 10x - 10
3x(x) - 3x(1) + 10(x) - 10(1)
3x(x - 1) + 10(x - 1)
(3x + 10)(x - 1)

The answer is D.
5 0
3 years ago
Read 2 more answers
What is the slope of a line that is perpendicular to the line shown.
sertanlavr [38]

Answer:

3/4

Step-by-step explanation:

First of all, we need to calculate the slope of the line shown. This can be computed as:

m=\frac{\Delta y}{\Delta x}

where

\Delta y = y_2-y_1 is the increment along the y-direction

\Delta x = x_2 - x_1 is the increment along the x-direction

We can choose the following two points to calculate the slope of the line shown:

(-3,2) and (0,-2)

And so, the slope of the line shown is

m=\frac{-2-(2)}{0-(-3)}=-\frac{4}{3}

Two lines are said to be perpendicular if the slope of the first line is the negative reciprocal of the slope of the second line:

m_2 = -\frac{1}{m_1}

Using m_1 = -\frac{4}{3}, we find that a line perpendicular to the line shown should have a slope of

m_2 = -\frac{1}{-4/3}=3/4

5 0
3 years ago
WILL GIVE BRAINLIEST: Which function has a removable discontinuity?
elena55 [62]

Answer:

First choice

Step-by-step explanation:

The discontinuity is removable if by reducing the fraction that discontinuity doesn't continue to exist as a discontinuity.

Example of, (x-1)/(x-1) has a a discontinuity at x=1 and it's removable because the fraction reduces to 1 which doesn't have a discontinuity at x=1.

Example not of, (x-1)/(x-2) has a discontinuity at x=2 and it is not removable because we can't get rid of the x-2 factor in the denominator.

The first choice has a discontinuity at x=-1 and it is removable because x^2-x-2=(x-2)(x+1) and the x+1's will cancel on top and bottom making the point at x=-1 a removable discontinuity.

8 0
3 years ago
Which of the following is a list of unlike terms, or terms that cannot be combined?
Vilka [71]

Answer:

C

Step-by-step explanation:

C is the only choice where all given options have different or no coefficients.

3 0
3 years ago
If JM = 5x – 8 and LM = 2x - 6, which expression represents JL?
Anastasy [175]

Answer:

3x-2

Step-by-step explanation:

JK =JL+LM

5x-8=JL +(2x -6)

JL = 5x-8 -2x+6

JL = 3x-2

6 0
3 years ago
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