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Alex Ar [27]
3 years ago
11

Please I need help how do you solve 5 + x to the 2nd power = 2x2 + 13

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

it has no real solutions

Step-by-step explanation:

5 + x² = 2x² + 13

first simplify by moving the 2x² to the left and the 5 to the right:

x² - 2x²=  13 - 5

- x²=  8

x = +/- √-8 has no (real) solutions

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A technology manufacturer is a supplier of fiber optic cables. They are interested in expanding their business and offering fibe
ExtremeBDS [4]

Answer:

B.alternative hypothesis

Step-by-step explanation:

In this case, the null hypothesis is that 45% of internet providers currently offer fiber optic internet in the United States.

The claim that the proportion of fiber optic internet providers is different from 45% is an alternative hypothesis since it directly contradicts the null hypothesis presented.

The answer is B. alternative hypothesis

8 0
3 years ago
The length of a rectangular garden is 3yd more than twice it’s width. The perimeter of the garden is 36yd. What are the width an
Basile [38]
2L + 2W = 36
2(3+2W) + 2W = 36
6 + 4W + 2W = 36
6W + 6 = 36
        -6  = -6
6W=30
W= 30/6 = 5     L= 3 + 2W = 3 +2 (5) = 3 +10= 13

Width is 5
Length is 13


7 0
4 years ago
What is the value of x when h(x)=-3? -7
Pachacha [2.7K]

Answer:

○ -1

Step-by-step explanation:

Looking closely at this piecewise function, when the line on the left-hand side intersects at <em>-</em><em>3</em><em> </em><em>=</em><em> </em><em>y</em><em>,</em><em> </em><em>x</em><em> </em>is -1.

I hope this helps, and as always, I am joyous to assist anyone at any time.

7 0
3 years ago
Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

C(x) = 50x + 300

And the revenue function is given by:

R(x) = 90x - 0.5x^2

The profit function is given by the revenue minus the cost, so we have:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

x_v = -b/2a = 80/2 = 40

Using this value of x, we can find the maximum profit:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0
3 years ago
Which of the following numbers is a factor of 78?
Aloiza [94]

Step-by-step explanation:

78 = 2 * 39 = 2 * 3 * 13.

Since 6 = 2 * 3 and its factors can be found in 78,

Hence the answer is 6. (C)

4 0
3 years ago
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