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ivanzaharov [21]
3 years ago
14

Use the properities to find the sum or product of 93+[68+7]

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer:

the answer for this questionis 93(68+7)

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3. A local pizza restaurant has two options for birthday parties; the Premium Plan and the
Nitella [24]

Answer:

Most likely C .

Step-by-step explanation:

The premium plan charges 20 dollars per cake. (+ 20) and $5 per child (5x) for pizza.

The premium plan would represent: 5x + 20

The basic plan would charge $6  per child for pizza.

This would be: 6x

In a equation when the cost of the premium plan is the same as the basic plan, 20 + 5x = 6x would be the best for modeling.  

4 0
4 years ago
HELP NO LINKS OR TROLLING
jekas [21]

Answer:

20.28 cm²

Step-by-step explanation:

The rectangle on the bottom is 7 cm by 2 cm.

The semicircle has a diameter of 7 cm - 1 cm - 2 cm = 4 cm

diameter = 4 cm

radius = diameter/2 = 2 cm

total area = area of semicircle + area of rectangle

total area = (1/2)πr² + LW

total area = (1/2)(3.14)(2 cm)(2 cm) + 7 cm × 2 cm

total area = 20.28 cm²

3 0
2 years ago
In how many ways can 15 runners finish first, second, and third?
Dovator [93]

Answer:

i know its more than 720 not too sure on the exacts tho

Step-by-step explanation:

sorry:(

5 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST TO QUICKEST RESPONSE
Jlenok [28]

Answer:

x = 16

the added 5 plus 11 makes 16

But to the nearest tenth the answer is x = 0

<3 Enjoy,

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7 0
3 years ago
A sporting goods store believes the average age of its customers is 38 or less. A random sample of 40 customers was​ surveyed, a
pashok25 [27]

Answer:

Test statistics = 2.85

P-value = 0.002

Step-by-step explanation:

We are given that a sporting goods store believes the average age of its customers is 38 or less.

A random sample of 40 customers was​ surveyed, and the average customer age was found to be 41.6 years and the standard deviation for customer age is 8.0 years.

Null Hypothesis, H_0 : \mu <= 38 years

Alternate Hypothesis, H_1 : \mu > 38 years

The test statistics we will use here is;

                 T.S. = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean = 41.6 years

               \sigma = population standard deviation = 8 years

               n = sample size = 40

So, test statistics = \frac{41.6-38}{\frac{8}{\sqrt{40} } } = 2.85

At 5% level of significance, the z table gives critical value of 1.6449. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject the null hypothesis and conclude that average age of its customers is more than 38 years.

P-value is given by, P(Z > 2.85) = 1 - P(Z <= 2.85) = 1 - 0.99781 = 0.002 .

4 0
4 years ago
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