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prisoha [69]
3 years ago
11

Julia needs to make a box in the shape of a rectangular prism with a height of 3 inches and a volume of 243 cubic inches. The di

mensions, in inches, must be whole numbers greater than 1. Julia claims that the length and the width must be equal. Part A: What dimensions would support Julia's claim about the length and with of the box? Part B: What dimensions would not support Julia's claim about the length and width of the box. Part A length =______________ Part A width=_____________________. Part B length_________________Part B Width=_____________________.
Mathematics
2 answers:
umka2103 [35]3 years ago
7 0
The volume of a rectangular prism is equal to length*width*height. In this case, we have V = 243 and H = 3.
243 = LW(3), so LW = 81, where L & W are whole numbers greater than 1. There are only 3 possible pairs of values for this: 27*3, 9*9, and 3*27 (we cannot use 1*81 or 81*1, since we need dimensions > 1).
Part A. This could be true if Length = 9 in and Width = 9 in, as 9*9 = 81.
Part B. The claim could be false if Length = 27 in and Width = 3 in, as 27*3 = 81, but 27 is not equal to 3.
*Note that the width cannot be longer than the length.
natulia [17]3 years ago
6 0
Part A.
 sqrt 81 = 9; L = 9 ; W = 9 inches

Part B.
if length =27 , width =3, though 27*3 = 81 but then 27 is not equal 3. So false
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{x₁, x₂, ...}

The total number of permutations for the K elements can be found in the next way.

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For the second element in the set, we have (K - 1) options (because we already choose one)

For the third element we have (K - 2) options, and so on.

The total number of permutation is equal to the product between the numbers of options for each position's element, then the number of permutations for K elements is:

permutations = K*(K - 1)*(K - 2)*....*2*1 = K!

Now suppose that we have a set of N elements, and we want to make groups of K elements.

The total number of different combinations of K elements is given by the equation:

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In this case we have 15 objects (then  N = 15) and we take 7 at the time (Then K = 7)

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Then the total number of different sets is:

C(15*7)*7!

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So we have 6,436 combinations, and each one of these combinations has 7! permutations.

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if we combine these we get:

Combinations*Permutations = 6,435*5,040 = 32,432,400

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