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ololo11 [35]
3 years ago
15

Kay sees a jacket in New York costing $170

Mathematics
1 answer:
ANEK [815]3 years ago
4 0

Answer:

its cheaper in new York by $1.60

Step-by-step explanation:

132 x 1.30 = 171.60

if the jacket is $170 in new York it is cheaper

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Based on the diagram, which expresses all possible
qaws [65]

The expression that expresses all possible lengths of segment AB is 27 < AB < 81. The correct option is the second option 27 < AB < 81

<h3>Properties of a triangle</h3>

From the question, we are to determine the expression that expresses all possible lengths of segment AB

From one of the properties of a triangle,

The <u>third side</u> of any triangle is greater than the difference of the other <u>two sides</u>; and the <u>third side</u> of any triangle is lesser than the sum of the <u>two other sides</u>

Then, we can write that

AB < 27 + 54

and

AB > 54 - 27

Putting the two inequalities together, we get

54 - 27 < AB < 27 + 54

27 < AB < 81

Hence, the expression that expresses all possible lengths of segment AB is 27 < AB < 81. The correct option is the second option 27 < AB < 81

Learn more on the Properties of a triangle here: brainly.com/question/1851668

#SPJ1

3 0
2 years ago
NEED HELP ASAP PLEASE WILL GIVE BRAINLYEST
Tomtit [17]

Answer:

True

Step-by-step explanation:

One is the opposite of the other

8 0
3 years ago
Read 2 more answers
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
Urgent help pleaseeeeeee
Helga [31]

Answer:

2x - 10 = 10 - 3x

Simplifying

2x + -10 = 10 + -3x

Reorder the terms:

-10 + 2x = 10 + -3x

Solving

-10 + 2x = 10 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.

-10 + 2x + 3x = 10 + -3x + 3x

Combine like terms: 2x + 3x = 5x

-10 + 5x = 10 + -3x + 3x

Combine like terms: -3x + 3x = 0

-10 + 5x = 10 + 0

-10 + 5x = 10

Add '10' to each side of the equation.

-10 + 10 + 5x = 10 + 10

Combine like terms: -10 + 10 = 0

0 + 5x = 10 + 10

5x = 10 + 10

Combine like terms: 10 + 10 = 20

5x = 20

Divide each side by '5'.

x = 4

Simplifying

x = 4

3 0
3 years ago
Read 2 more answers
I need you to explain your answer, please.
Alex787 [66]

Answer:

7√6 - 5√7  

Step-by-step explanation:

5√7 + 12√6 - 10√7 - 5√6    (rearranging)

= (5√7 - 10√7) + (12√6  - 5√6)   (factor out √6 and √7 respectively)

= (5 - 10) √7  + (12  - 5)√6

=  -5√7  + 7√6  (rearrange)

=  7√6 - 5√7  

4 0
3 years ago
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