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aksik [14]
3 years ago
13

Please help me!

Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0

A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.

We can use the Pythagorean formula to find the other leg of the right triangle.

a²+b²=c²

Where a and b are the legs of the triangle and c is the hypotenuse.

According to the given problem,

one leg: a= 5m and hypotenuse: c=13√5 m.

So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,

5²+b²=(13√5)²

25 + b² = 13²*(√5)²

25 + b² = 169* 5

25+ b² = 845

25 + b² - 25 = 845 - 25

b² = 820

b =√ 820

b = √(4*205)

b = √4 *√205

b = 2√205

b= 2* 14.32

b = 28.64

So, b= 28.6 (Rounded to one decimal place)

Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).

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How many permutations of a 7-digit phone number exist if any number 0-9 may be used but repetition is not allowed?
Blizzard [7]

Answer:

10!/3!

Step-by-step explanation:

5 0
1 year ago
The scale on the map is stated as 1 : 200000. A main road connects two towns which are 28 kilometres apart. How far will it be o
loris [4]

Answer:

The distance on the map between the two towns=14 cm

Step-by-step explanation:

Step 1

Express the scale as;

1:200,000 this means that 1 cm on the map represents 200,000 cm on the road, 1 cm:200,000 cm

Step 2

Convert 28 kilometers to m

1 meter=1,000 kilometers

28 kilometers=28×1,000=28,000 meters

Convert 28,000 meters to centimeters

1 meter=100 centimeters

28,000 meters=28,000×100=2,800,000 centimeters

Step 3

Using the scale factor of 1:200,000 convert 2,800,000 cm on the road can be converted to map measurements as follows;

Distance on the map=scale factor×distance on the road

where;

scale factor=1/200,000

distance on the road=2,800,000 cm

replacing;

Distance on the map=(1/200,000)×2,800,000

Distance on the map=14 cm

The distance on the map between the two towns=14 cm

5 0
3 years ago
Listed below are the measured radiation emissions​ (in W/kg) corresponding to cell​ phones: A,​ B, C,​ D, E,​ F, G,​ H, I,​ J, a
Sophie [7]

Answer: a. Mean = 0.696364

b. Median = 0.64

c. Midrange = 0.895

d. There is no Mode

e. 2. The maximun data value is the most relevant statistic, because it is closest to the limit of 1.6W/kg and that cell should be avoided.

Step-by-step explanation:

a) Mean is an average number of the data set, calculated by the sum of all the value divided by the quantity of the set:

mean = \frac{0.75+0.22+1.23+0.64+0.54+0.24+0.81+1.57+0.29+1.02+0.35}{11}

mean = 0.696364

b) Median is the middle number in the list of numbers. In this case, since there are 11 elements in the set, the middle number is:

sorted numbers of the data set:

0.22 0.24 0.29 0.35 0.54 0.64 0.75 0.81 1.02 1.23 1.57

median = 0.64

c) Midrange is another type of average number. It is calculated as:

midrange = \frac{high+low}{2}

midrange = \frac{1.57+0.22}{2}

midrange = 0.895

d) Mode is the number that appears most often in the list of numbers. For this data set, each number appears only one time, so there is no mode.

Mode = 0

e) According to the question, cell phone radiation is dangerous when it is higher than 1.6W/kg. The cell phone with the maximum data value (1.57 W/kg) should be avoided, since it is too close to the limit described.

So, the measures of center are not the most important statistic to be observed but the maximum data value.

7 0
3 years ago
If john gets his license, then he will buy a car.
GenaCL600 [577]
What is the question lol
8 0
3 years ago
Read 2 more answers
HELP ^^^^ ignore what i picked it was an accident
koban [17]

Answer:

everything is in the picture

6 0
2 years ago
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