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8_murik_8 [283]
3 years ago
10

Write 17/9 as a decimal

Mathematics
2 answers:
denis23 [38]3 years ago
6 0
Divide 17 by 9
1.8888
Aleks04 [339]3 years ago
5 0

Answer:

1/2=0.5

-4 4/25=-4.16

1/8=0.125

3/16=0.1875

-33/50=-0.66

-17/40=-0.425

5 7/8=5.875

9 3/8=9.375

Step-by-step explanation:

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1/4 x -2&gt;1<br><br> and the grater than sign has a line under it.
antoniya [11.8K]

For this inequality x is greater than or equal to 12

8 0
3 years ago
In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm
tangare [24]

Answer:

AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD

Consider right triangle CAH.By the Pythagorean theorem,

CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8

The length cannot be negative, so CD=8 cm and

CA=\sqrt{3}CD=8\sqrt{3}\ cm

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

AB=2CA=16\sqrt{3}\ cm

By the Pythagorean theorem,

BC^2=AB^2-AC^2\\ \\BC^2=(16\sqrt{3})^2-(8\sqrt{3})^2=256\cdot 3-64\cdot 3=576\\ \\BC=24\ cm

3 0
3 years ago
Berto has $12 and 3.75 per gallon how much gas can he get
KonstantinChe [14]
Berro can get 3 gallons of gas
6 0
3 years ago
Read 2 more answers
What is the hight of a Building 1 Angle 71o Distance 20 meters
vlabodo [156]

The height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.

<h3>What is trigonometry?</h3>

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We have:

Angle = 71 degree

Distance between A and B = 20 meters

Let's suppose the height of the building is x meters.

From the right angle triangle applying the tan ratio:

tan71 = x/20

x = 58.08 meter

Thus, the height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.

Learn more about trigonometry here:

brainly.com/question/26719838

#SPJ1

6 0
2 years ago
The average basketball has a diameter of 9.5 inches. What is the volume of an average basketball?
Elodia [21]

the formula for volume of sphere is 4/3||r^3

diameter=2radius

in the formula we need to have radius but we have been given diameter so we convert diameter to radius

d=2r

r=d/2

9.5÷2

4.75

6 0
3 years ago
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