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3 years ago

The number -2.34 can be found between which two integers? (Full question above)

Mathematics

2 answers:

Orlov [11]3 years ago

7 0

Answer:

last option

Step-by-step explanation:

imagine a number line

________________________________________________

-3 -2 -1 0 1 2 3

-2.34 would be found somewhere over there

coldgirl [10]3 years ago

5 0

The last option, between -2 and -3.
If you ignore the negative -2.34 and imagine it is 2.34, with a number line you can see it’s between 2 and 3, so with -2.34 it is simply between -2 and -3.

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Three-fourths was subtracted from a number, and then 5 1/4 was added to the result. The sum was -7.

Alika [10]

Answer:

1 1/4 is the answer

Step-by-step explanation:

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6 0

3 years ago

What's 2x+3y=6 and x-3y=9?

Vedmedyk [2.9K]

Set up a system of equations:

2x+3y=6
x-3y=9

You can solve this with elimination by adding the two equations together:

3x+0y = 15
3x=15
x=5

Then, plug this value back into either of the original equations to find the y value:

5-3y=9
-3y=4
y= -4/3

The point of intersection is (5,-4/3)

4 0

3 years ago

Jaya is the middle of three siblings whose ages are consecutive even integers. If the sum of their ages is 84,find Jaya’s age

Svetach [21]

12345612345612317890

7 0

11 months ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

2 years ago

Megan surveyed a random sample of 60 students at her school and found that 42 of them ride the bus to school each day. if there

Dmitry_Shevchenko [17]

42/60, x/320. 320/60=5.33333, 42*5.33333=224. So, about 224 students would ride the bus.

4 0

2 years ago