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3 years ago

What is the solution to 7 × p = -56? A. -49 B. -8 C. 8 D. 49

Mathematics

1 answer:

Serga [27]3 years ago

4 0

Answer:

-8

Step-by-step explanation:

Hello!

What we do to one side of the equation we do to the other side

7 * p = -56

Divide both sides by 7

p = -8

The answer is -8

Hope this helps!

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Gavin rolls a fair dice 48 times.<br> How many times would Gavin expect to roll an even number?

pantera1 [17]

Answer: The number of times Gavin expect to roll an even number =24

Step-by-step explanation:

Given: Numbers of a fair dice = 1, 2, 3, 4, 5, 6

even numbers = 2, 4, 6

odd numbers = 1, 3, 5

Probability of getting an even number = $\dfrac{3}{6}=\dfrac12$

If Gavin rolls a fair dice 48 times.

Then, the number of times Gavin expect to roll an even number = $48\times\dfrac12=24$

Hence, the number of times Gavin expect to roll an even number =24

6 0

2 years ago

Whoever gets it right can have brainliest, but answer ASAP!

sveta [45]

Answer:

-29

Step-by-step explanation:

(-4 + -3) x 2^2 - 1

follow order of operations PEMDAS

Parentheses:

(-4 + -3) x 2^2 - 1

(-7) x 2^2 -1

exponents:

(-7) x 4 - 1

multiplication

-28 - 1

subtraction

-29

3 0

2 years ago

Read 2 more answers

A swimming pool whose volume is 10 comma 000 gal contains water that is 0.03% chlorine. Starting at tequals0, city water conta

Katarina [22]

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.

Remember, 1 h = 60 minutes. The initial value problem is

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x = - 6* 10⁻⁴*(3x - 10⁻¹) x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C or |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s

7 0

3 years ago

Which sequences are arithmetic? Check all that apply.

spin [16.1K]

Answer:

3) 18, 5.5, –7, –19.5, –32, … sequence is in Arithmetic Progression.

5) 16, 32, 48, 64, 80 sequence is in Arithmetic Progression.

Step-by-step explanation:

If, a, b, c ,k, e ... is a given sequence.

Then the above sequence is in AP if b - a = c - b = k - c = ...

or, each term has same COMMON DIFFERENCE (d).

Here, take each sequence and check for the value of d.

1) –5, 5, –5, 5, –5, …

Here, 5 - (-5) = 10, -5 - 5 = -10

and 10 ≠ -10. So the sequence is NOT in Arithmetic Progression.

2)96, 48, 24, 12, 6

Here, 48 - 96 = -48, 24 - 48 = -24

and -48 ≠ -24. So the sequence is NOT in Arithmetic Progression.

3)18, 5.5, –7, –19.5, –32, …

Here, 5.5 - 18 = -12.5 , -7 - 5.5 = -12.5 ..

and -12.5 is the common difference.

So the sequence is in Arithmetic Progression.

4)–1, –3, –9, –27, –81, …

Here, -3-(-1) = - 2 -9 - (-3) = -6

and -2 ≠ -6. So the sequence is NOT in Arithmetic Progression.

5)16, 32, 48, 64, 80

Here, 32 - 16 = 16 , 48 - 32= 16 ..

and 16 is the common difference.

So the sequence is in Arithmetic Progression.

6 0

3 years ago

Read 2 more answers

What is value of -x^2 -4x -11 if x = -3

maksim [4K]

Your answer is -8. I did it out of order. My apology.

3 0

3 years ago

Read 2 more answers