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lawyer [7]
3 years ago
15

what is the relationship between the scale divisions marked on the graduated cylinders and the estimated uncertainty in the volu

me measurements?

Chemistry
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

  • <em>The relationship between the scale divisions marked on the graduated cylinders and the estimated uncertainty in the volume measurements is</em> that <u>the larger the divisions the larger the uncertainty, and the smaller the divisions the smaller the uncertaintity.</u>

Explanation:

In general, <em>graduated cylinders</em> are marked with divisions (lines) at equal spaces or intervals. There are divisions that show the measure with a number and a series of intermediate not numbered divisions in between two numbered lines.

The <em>uncertainty </em>of the instrument is determined as half the difference between two consecutive marks.

So, the larger the interval of two consecutive marks the larger the uncertainty.

The attached image, taken from brainly.com/question/13102373, shows you some marks in a graduated cylinder.

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What is the mass of 20.0 mL solution if its density<br> is 1.84 g/mL?
gogolik [260]

Answer:

mass=36.8 g

Explanation:

density = mass/ volume

mass= density × volume

mass= 1.84× 20.0

mass=36.8 g

3 0
3 years ago
suppose medical records indicate that the length of newborn babies (in inches) is normally distributed with a mean of 20 and a s
Tanya [424]

Answer:

  • <u>0.6826 (68.26%)</u>

Explanation:

<u>1) Find the z-scores:</u>

  • z = [X - μ ] / σ

a) z-score for 22.6 inches length

  • X = 22.6
  • μ = 20
  • σ = 2.6

  • z = [ 22.6 - 20 ] / 2.6 = 1.00

b) z-score for 17.4 inches length

  • X = 17.4
  • μ = 20
  • σ = 2.6

  • z = [ 17.4 - 20 ] / 2.6 =  - 1.00

<u>2) Probability</u>

Then, you have to find the probability that the length of an infant is between - 1.00 and 1.00 standards deviations (σ) from the mean (μ).

That is a well known value of 68%, which is part of the 68-95-99.7 empirical rule.

The most exact result is obtained from tables and is 68.26%:

  • 1 - P (z ≥ 1.00) - P (z ≤ - 1.00) = 1 - 0.1587 - 0.1587 = 0.6826 = 68.26%
5 0
3 years ago
Drag the tiles to the correct locations on the equation. Not all tiles will be used.
mel-nik [20]

Answer:

Tile 52 and three are incorrect

Explanation:

6 0
2 years ago
Two common methods to generate an aldehyde is by oxidation of an alcohol and through ozonolysis.
kotykmax [81]

Answer:

<u>a</u><u>.</u><u> </u><u>True</u><u>.</u>

Explanation:

Only primary and secondary alcohols can oxidise to give an aldehyde. But a weak oxidizing agent must be used to prevent formation of a carboxylic acid or ketone.

weak oxidizing agents: Chromyl chloride, silver/oxygen/500°C

take an example of <u>e</u><u>t</u><u>h</u><u>a</u><u>n</u><u>o</u><u>l</u><u>:</u>

<u>{ \bf{CH _{3} CH_{2}OH \:  \:  \frac{Ag/O_{2} }{500 \degree C}  >  \:  \:CH _{3} CHO}}</u>

<u>{ \sf{CH _{3} CHO \:  \: is \: ethanal}}</u>

<u>B</u><u>y</u><u> </u><u>o</u><u>z</u><u>o</u><u>n</u><u>o</u><u>l</u><u>y</u><u>s</u><u>i</u><u>s</u><u>:</u>

Here, reactants are Ozone gas, Carbon tetrachloride at a temperature (<20°C), ethanoic acid, zinc and water.

take an example of propanol:

if it undergoes ozonolysis, it gives ethanal and methanal.

5 0
3 years ago
Read 2 more answers
A gas has a volume of 420 L at a temperature of -42.0 degrees celsius. What volume will the gas occupy at 18.0 degrees celsius?
Hoochie [10]

Formula

V/T = V1/T1

Givens

V = 430 L

T = - 42 °C = - 42 + 273 = 231°K

V1 = ??

T1 = 18°C + 273 = 291°K

The pressure is a constant.

Solution

420/231 = V1/291         Multiply by 291

420*291 / 231 = V1

V1 = 122220 / 231

V1 = 521.1 L  

6 0
4 years ago
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