<u>Answer:</u> The correct answer is saturated solution.
<u>Explanation:</u>
For the given options:
Dilute solutions are defined as the solutions in which solute particles are present in less very amount than the solvent particles.
Unsaturated solutions are defined as the solutions where more and more of solute particles can be dissolved in the given amount of solvent.
Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent. The concentration of the solute particles that can be dissolved in a solution is maximum.
Supersaturated solutions are defined as the solutions where more amount of solute particles are present than the solvent particles.
From the above information, we conclude that the given solution is saturated solution.
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, the volume per mole of gas or the molar volume-Vm is 22.4 liters/mol.
Volume of Argon V1 = 5.0 L Pressure of Argon P1 = 2 atm Final temperature T2 = 30 C = 30 + 273 = 303 K Volume at final temperature V2= 6 L Pressure at final temperature P2 = 8 atm We know that (P1 x V1) / T1 = (P2 x V2) / T2 (2 x 5)/ T1 = (8 x 6)/ 303 => T1 = (10 x 303) / 48 Initial Temperature T1 = 3030 / 48 = 63.12 Initial Temperature = -209. 8 C
