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irga5000 [103]
3 years ago
11

What is the name of a solution whose concentration of solute is equal to the maximum concentration that is predicted from the so

lute's solubility?
dilute
saturated
unsaturated
supersaturated
Chemistry
2 answers:
faltersainse [42]3 years ago
7 0

<u>Answer:</u> The correct answer is saturated solution.

<u>Explanation:</u>

For the given options:

Dilute solutions are defined as the solutions in which solute particles are present in less very amount than the solvent particles.

Unsaturated solutions are defined as the solutions where more and more of solute particles can be dissolved in the given amount of solvent.

Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent.  The concentration of the solute particles that can be dissolved in a solution is maximum.

Supersaturated solutions are defined as the solutions where more amount of solute particles are present than the solvent particles.

From the above information, we conclude that the given solution is saturated solution.

Pavel [41]3 years ago
6 0

Answer:

The correct answer is saturated

Explanation:

Hello!

Let's solve this!

Diluted solutions are when you have more solvent than solute.

The saturated solution is when it has the same amount of solute as of solvent.

The unsaturated solution is the solution in which the solvent can still receive more solute.

The supersaturated solution is when it has more solute than the one that can dissolve the solvent.

Then the correct answer is saturated where the solvent already has the maximum amount of solute that can dissolve.

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Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial conc
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Explanation:

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∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]

                      [ ]initial         change         [ ]eq

CO(g)              0.27 M       0.27 - x        0.27 - x

H2(g)              0.49 M       0.49 - x        0.49 - x

CH3OH(g)          0                0 + x               x = 0.11 M

replacing in Ka:

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⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)

⇒ Ka = (0.11) / (0.38)²(0.16)

⇒ Ka = 4.76108

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