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natima [27]
3 years ago
10

This data was collected after conducting an experiment about the amount, in liters, of water a specific plant needs per month. A

n accepted value for the measurement is 6 liters. These are the collected experimental values.
Which values in the collected data are precise? Check all that apply.

1.1 liters
1.2 liters
1.5 liters
6.0 liters
8.1 liters
Chemistry
2 answers:
Aneli [31]3 years ago
5 0

Answer:

1.1 liters

1.2 liters

1.5 liters

Explanation:hope you do good in edge

Effectus [21]3 years ago
4 0

Answer:

1.1 liters

1.2 liters

1.5 liters

Explanation:

Precision in data refers to how close the experimental values of an experiment are to one another irrespective of the true or accepted value. In other words, a set of values are said to be PRECISE if they are close to one another.

In this case, data was collected after conducting an experiment about the amount, in liters, of water a specific plant needs per month. However, according to the set of experimental values provided, only 1.1 litres, 1.2litres and 1.5litres are close to one another and, hence, are said to be PRECISE even if they are not close to the accepted value of 6litres.

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natka813 [3]

100.0 g KClO₃ × 1 mol KClO₃/122.55 g KClO₃ × 2 mols KCl/2 mols KClO₃= 0.8160 mols of KCl

100.0 g KClO₃ × 1 mol KClO₃/122.55 g KClO₃ × 3 mols O₂/ 2 mols KClO₃= 1.224 mols of O₂

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122.55 g is molar mass of potassium chlorate


4 0
3 years ago
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How many grams of sodium chloride are required to prepare 500.0 ml of a 0.100 m solution?
scoray [572]

Answer:

  • <u>2.92 g</u>

Explanation:

<u>1) Data:</u>

a) V = 500.0 ml = 0.500 liter

b) M = 0.100

c) mass = ?

<u>2) Formulae:</u>

a) Molarity: M = n / V

b) Number of moles: n = mass in grams / molar mass

<u>3) Solution</u>

a) M = n / V ⇒ n = M × V = 0.1000 M × 0.500 liter = 0.0500 mol

b) molar mass NaCl = 58.443 g/mol

c) mass = n × molar mass = 0.0500 mol × 58.443 g/mol = 2.92 g

Answer: 2.92 g

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3 years ago
What is the pH of a 2.1 M solution of HClO4?
Flura [38]
Since HCl04 is a strong acid, being [H+], and a molarity of 2.1 M.

To solve for pH:

pH = -log (M) = -log(2.1M) = -0.32, which is clearly a negative number.

However, to verify the answer, just use the pH meter in determining the pH of the solution.
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4 0
4 years ago
CH4 with pressure 1 atm and volume 10 liter at 27°C is passed into a reactor with 20% excess oxygen, how many moles of oxygen is
BaLLatris [955]

Answer : The moles of O_2 left in the products are 0.16 moles.

Explanation :

First we have to calculate the moles of CH_4.

Using ideal gas equation:

PV=nRT

where,

P = pressure of gas = 1 atm

V = volume of gas = 10 L

T = temperature of gas = 27^oC=273+27=300K

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times (10L)=n\times (0.0821L.atm/mol.K)\times (300K)

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Now we have to calculate the moles of O_2.

The balanced chemical reaction will be:

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that,

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So, 0.406 mole of CH_4 react with 2\times 0.406=0.812 moles of O_2

Now we have to calculate the excess moles of O_2.

O_2 is 20 % excess. That means,

Excess moles of O_2 = \frac{(100 + 20)}{100} × Required moles of O_2

Excess moles of O_2 = 1.2 × Required moles of O_2

Excess moles of O_2 = 1.2 × 0.812 = 0.97 mole

Now we have to calculate the moles of O_2 left in the products.

Moles of O_2 left in the products = Excess moles of O_2 - Required moles of O_2

Moles of O_2 left in the products = 0.97 - 0.812 = 0.16 mole

Therefore, the moles of O_2 left in the products are 0.16 moles.

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