Question

What are the approximate values of the minimum and maximum points of

Answer 1

Answer: The answers A

Step-by-step explanation:

Answer 2

Find critical points by setting derivative equal to 0.

Derivative of polynomial is found by multiplying coefficient by exponent, then subtracting 1 from exponent.

f'(x) = 5x^4 - 30x^2 + 9 = 0

This is in quadratic form, use quadratic formula to find x^2

$x^2 = \frac{15 \pm 6\sqrt{5}}{5} \\ \\ x = \pm\sqrt{\frac{15 \pm 6\sqrt{5}}{5}} = \pm 0.5628, \pm 2.384$