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blsea [12.9K]
3 years ago
13

What are the approximate values of the minimum and maximum points of

Mathematics
2 answers:
Vaselesa [24]3 years ago
4 0

Answer: The answers A

Step-by-step explanation:

Serga [27]3 years ago
3 0
Find critical points by setting derivative equal to 0.

Derivative of polynomial is found by multiplying coefficient by exponent, then subtracting 1 from exponent.

f'(x) = 5x^4 - 30x^2 + 9 = 0

This is in quadratic form, use quadratic formula to find x^2

x^2 = \frac{15 \pm 6\sqrt{5}}{5}  \\  \\ 
x  = \pm\sqrt{\frac{15 \pm 6\sqrt{5}}{5}} = \pm 0.5628, \pm 2.384
You might be interested in
Q20-23 with steps pls
just olya [345]

20: Let x be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30

Rearrange the left hand side as

\dfrac{4x-3x}{24}=30

And multiply both sides by 24 to get

x=720

21: Let M and J be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

M=3J+11

If they both get 9 more marbles, Mike will have M+9 marbles, and Judy will have J+9 marbles. So, we have

M+J+18=93 \iff M+J=75 \iff M=75-J

Plug this value in the first equation and we have

75-J=3J+11 \iff 4J=64 \iff J=16

And we deduce

M=16\cdot 3 + 11=59

So, the difference is  

M-J=59-16=43

22: Let x,y,z be the number of $10, $20 and $50 coupon, respectively. We're given:

\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}
We can write the third equation by substituting the expressions for x and z:
[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38

Rearrange as follows:

(2y+3)+y+\left(\dfrac{1}{2}y\right)=38 \iff \dfrac{7}{2}y=35 \iff 7y=70 \iff y=10

And now we can deduce the number of the other coupons:

x=2\cdot 10+3=23,\quad z=\dfrac{1}{2}\cdot 10=5

So, the total value is

23\cdot 10+10\cdot 20+5\cdot 50=230+200+100=530

23:  a) In order to find the first three terms of the sequence, you just need to plug n=1,2,3:

a_1=4\cdot 1+3=7,\quad a_2=4\cdot 2+3=11,\quad a_3=4\cdot 3+3=15

b) We have

a_r = 4r+3=71 \iff 4r=68 \iff r=\dfrac{68}{4}=17

c) 105 is a term of the sequence if and only if there exists an integer k such that

a_k=4k+3=105 \iff 4k = 102 \iff k=\dfrac{102}{4}=25.5

So, 105 is not a term of the sequence.

8 0
4 years ago
Which pair of triangles can be proven congruent by SAS?
wolverine [178]

Answer:

top choice

Step-by-step explanation:

For SAS, you need a side followed by an angle followed by another side of one triangle to be congruent to the corresponding parts of another triangle.

The top choice shows side-angle-side.

The middle choice shows angle-side-angle.

The bottom choice shows side-side-side.

Answer: top choice

3 0
3 years ago
Read 2 more answers
Write a function that models the distance D from a point on the line y = 9 x - 8 to the point (0,0) (as a function of x).
lakkis [162]

The function that models the distance D from a point on the line y = 9 x - 8 to the point (0,0) (as a function of x) is y = 9x

Given the equation of a line in standard form as y = 9x - 8

Get the slope of the line

mx = 9x

m = 9

Since the line passes through the origin (0, 0), substitute the slope and the point in the  point-slope form of the equation as shown below:

y-y_0=m(x-x_0)

y-0=9(x-0)\\y =9x

Hence the function that models the distance D from a point on the line y = 9 x - 8 to the point (0,0) (as a function of x) is y = 9x

Learn more here: brainly.com/question/15816805

4 0
3 years ago
Does the point (-4, 3) fall on the graph of this line? How do you know? Show your work. ( 2 points) PLEASE HELP ILL MARK BRAINLI
Elanso [62]

Answer:

Step-by-step explanation:

Since we know the line goes through points (8,9) and (2,4), we can construct a line in slope-intercept form

y = mx + b

where m is the slope and b is the Y-intercept.

The slope can be found using the two points provided:

\frac{y_{2} - y_{1}}{x_{2} - x_{1}}

\frac{9 - 4}{8 - 2}

\frac{5}{6}

The line is now represented as

y = \frac{5}{6}x + b

To solve for b, we can plug in one of the two points:

y = \frac{5}{6}x + b

(9) = \frac{5}{6}(8) + b

4 = \frac{20}{3} + b

b = \frac{-8}{3}

We know have our line:

y = \frac{5}{6}x - \frac{8}{3}

To determine if the point (-4, 3) falls on this line, we just plug the numbers into the equation and see if it holds true:

y = \frac{5}{6}x - \frac{8}{3}

(3) = \frac{5}{6}(-4) - \frac{8}{3}

3 = \frac{-10}{3} - \frac{8}{3}

3 = \frac{-18}{3}

3 = -6

This does not hold true, so the point is not on the line.

3 0
3 years ago
If the graph of f(x)=x2, how will the graph be affected if it is changed to f(x)=3x2?
Anastaziya [24]

There will be a vertical stretch with a factor of 3.

7 0
2 years ago
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