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Ahat [919]
4 years ago
7

The sum of a number and 17 is no less than 26

Mathematics
2 answers:
Sphinxa [80]4 years ago
7 0

Answer:

The equation is  x + 17 > 26

x > 9

Step-by-step explanation:

The sum of a number and 17 is no less than 26

Let "x" be a number.

The sum of a number and 17 = x + 17

No less than means ">"

So, the inequality is  x + 17 > 26

We can solve this inequality.

Solve for x.

Subtract 17 on both sides, we get

x + 17 - 17 > 26 - 17

x > 9

Tema [17]4 years ago
6 0
We put this into an algebraic equation, where <span>x = the number .
x + 17 > 26
x > 9

This </span>> is the greater than sign, we use this because it's no less than 26. 
Ideally we would use this sign:
<span>http://etc.usf.edu/clipart/41700/41712/fc_greateq_41712_md.gif 
because it could be equal to 26.

</span><span>The number is <u>greater or equal to 9</u>

</span>
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what is the common number to be subtracted from each term of the ratio 11:8 to get the new ratio 2:1.?​
JulijaS [17]

Answer:

5 should be subtracted  from each term

Step-by-step explanation:

\frac{11-x}{8-x}=\frac{2}{1}

Cross multiply,

1 * (11 - x) = 2*(8-x)

11 -x = 2*8 - 2*x

11 - x = 16 - 2x

Subtract 11 from both sides,

-x = 16 - 2x - 11

-x = 5 - 2x

Add 2x to both sides

-x +2x = 5 - 2 + 2x

x = 5

7 0
3 years ago
the map shows the route for a race. you are at a, which is 6000 feet from the first checkpoint b. the second checkpoint c is loc
Nimfa-mama [501]
<span>The two checkpoints are 4,920 ft. apart from each other. The total distance of the race is 15,840 ft. If checkpoint C half the distance between checkpoint B and the end of the race, the distance between Checkpoint B and the end of the race is 9,840 ft. Half of that distance is 4,920 ft.</span>
3 0
3 years ago
Find the values of x and y.
vova2212 [387]

Look at the picture.

We have the equation (1) 12x + 4y = 40.

We know, the sum of the acute angles in a right triangle is 90°.

Therefore we have the equation (2) (12x + 4y) + (17x - y) = 90

Substitute (1) to (2):

40 + 17x - y = 90        <em>subtract 40 from both sides</em>

17x - y = 50   (3)

We have the system of equations:

\left\{\begin{array}{ccc}12x + 4y = 40&|:4\\17x-y=50\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3x + y = 10\\17x-y=50\end{array}\right}\ \text{add both side of equations}\\.\qquad20x=60\qquad|:20\\.\qquad x=3

Substitute the value of x to (3)

17(3)-y=50\\51-y=50\qquad|-51\\-y=-1\to y=1

Answer: x = 3 and y = 1.

4 0
3 years ago
Find (a) arc length and (b) Area of a sector.
barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

\textsf{Arc length}=r \theta

\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta

\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}

<u>Calculation</u>

Given:

  • \theta=\dfrac{5 \pi}{8}
  • r = 15 cm

\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}

\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}

5 0
2 years ago
Which expression is equivalent to (3/4)^-2<br> A: -9/16<br> B: 16/9<br> C: -6/8<br> D: 9/16
UkoKoshka [18]
B is the answer B is the answer B is the answer B is the answer
7 0
3 years ago
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